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# D.S

Author Message
TAGS:
Manager
Joined: 09 Jun 2010
Posts: 79
Followers: 1

Kudos [?]: 9 [0], given: 17

D.S [#permalink]  29 Jul 2010, 22:37
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:43) correct 0% (00:00) wrong based on 2 sessions
240,120,60,30

In the sequnce above, each term after the first 1/2 of the preceding term. What is the least term of the sequnce is greater than 1 ?

a 32/15
b 16/15
c 15/8
d 15/4
e 15/2

pleas help with a formula
Math Expert
Joined: 02 Sep 2009
Posts: 29802
Followers: 4904

Kudos [?]: 53647 [0], given: 8167

Re: D.S [#permalink]  29 Jul 2010, 22:57
Expert's post
xmagedo wrote:
240,120,60,30

In the sequnce above, each term after the first 1/2 of the preceding term. What is the least term of the sequnce is greater than 1 ?

a 32/15
b 16/15
c 15/8
d 15/4
e 15/2

pleas help with a formula

There is no need for formula:
240, 120, 60, 30, 30/2, 30/4, 30/8, 30/16, 30/32<1. So the leas term more than 1 is 30/16=15/8.

But still if you need: $$\frac{30}{2^n}>1$$, where n is integer --> $$2^n<30$$ --> $$n<5$$ --> $$n=4$$ --> $$\frac{30}{2^n}=\frac{30}{2^4}=\frac{15}{8}$$.

_________________
Re: D.S   [#permalink] 29 Jul 2010, 22:57
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