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# d/s - adults & kids

Author Message
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Manager
Joined: 10 Oct 2005
Posts: 62
Followers: 1

Kudos [?]: 0 [0], given: 0

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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
There are 3 groups of people. Adults, kids who are 7 years old or older, kids who are younger than 7. Those people are to attend an event, the entry fees charged are 100 for each of adults, 75 for each of the kids who are 7 years old or older, 50 for each of kids who are younger than 7. The total of the fees is 500,000. What is the total number of kids?

1). The number of adults is 125.
2). The ratio of the fees from the adults to the fees from the kids is 1:3

OA is E but i think it should be D as we have to determine total number of kids....
Senior Manager
Joined: 30 Oct 2004
Posts: 286
Followers: 1

Kudos [?]: 16 [0], given: 0

I get E

For starters.. is it 500,000 or 50,000?

Let adult = A, 7 or old = B, less than 7 = C
Equation from question stem is
100A + 75B + 50C = 500000 .... EQN1
Question asks what is B+C =?

1) A = 125
So we get from EQN1, 75B + 50C = 500,000 - 100(125) = 487,500
INSUFF. We cannot derive B+C from this info.

2) 100A/(75B+50C) = 1/3
300A = 75B + 50C
=> substitute in EQN1 we get 400A = 500,000 or A = 1250
So EQN1 becomes 75B + 50C = 500000 - 100(1250) = 475,000
From 1) & 2) we have two equations but can't really solve them as their coefficients are the same.... I think the total fees should be 50,000 which will lead to the same equation being formed in 1 and 2.

Hence E.
_________________

-Vikram

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