Last visit was: 24 Apr 2024, 21:29 It is currently 24 Apr 2024, 21:29

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Difficulty: Sub 505 Levelx   Probabilityx               
Show Tags
Hide Tags
User avatar
Intern
Intern
Joined: 04 Feb 2011
Posts: 36
Own Kudos [?]: 827 [17]
Given Kudos: 42
Location: US
Send PM
Most Helpful Reply
User avatar
Manager
Manager
Joined: 14 Feb 2011
Posts: 103
Own Kudos [?]: 400 [7]
Given Kudos: 3
Send PM
General Discussion
User avatar
Manager
Manager
Joined: 29 Jan 2011
Posts: 160
Own Kudos [?]: 711 [0]
Given Kudos: 87
Send PM
User avatar
Senior Manager
Senior Manager
Joined: 01 Feb 2011
Posts: 309
Own Kudos [?]: 324 [2]
Given Kudos: 42
Send PM
Re: Each of the eggs in a bowl is dyed red, or green, or blue. If one egg [#permalink]
2
Kudos
P(R) is not 1/5.

P(R) = R/(total)

Given that there are 5 Red . But we don't know the total . so we cannot calculate P(R) without knowing total.


1. Not sufficient
R=5
when G = 2 , B = 1 => P(G) = 2/8
when G=1, B=2 => P(G) = 1/8

2. Not Sufficient

P(B) = 1/3 = x/3x

But this doesn't tell us anything about B or total because P(B) = 1/3 , but it could also be 2/6 or 3/9 so on..

So we can have different B . Thus we can have different G combinations.

Together - Not Sufficient

P(B) = x/(3x) , R = 5

P(G) = 1- P( not G )

= 1- P(R or B)

But we cannot calculate this with out knowing P(R) and P(B).

Hence answer is E.





siddhans wrote:
From st 1 we get : probability of selecting 1 red = 1/5 --- Insufficient

From st 2 we get: probability of selecting 1 blue = 1/3 ---- Insufficient

Combining 1 and 2 we get =>

Probability of 1 red or 1 blue = 1/5 + 1/3

Probability of green = 1 - (1/5 + 1/3)



Hence should be C... What wrong with this logic ...Can someone explain the flaw?
User avatar
Manager
Manager
Joined: 29 Jan 2011
Posts: 160
Own Kudos [?]: 711 [0]
Given Kudos: 87
Send PM
Re: Each of the eggs in a bowl is dyed red, or green, or blue. If one egg [#permalink]
Spidy001 wrote:
P(R) is not 1/5.

P(R) = R/(total)

Given that there are 5 Red . But we don't know the total . so we cannot calculate P(R) without knowing total.


1. Not sufficient
R=5
when G = 2 , B = 1 => P(G) = 2/8
when G=1, B=2 => P(G) = 1/8

2. Not Sufficient

P(B) = 1/3 = x/3x

But this doesn't tell us anything about B or total because P(B) = 1/3 , but it could also be 2/6 or 3/9 so on..

So we can have different B . Thus we can have different G combinations.

Together - Not Sufficient

P(B) = x/(3x) , R = 5

P(G) = 1- P( not G )

= 1- P(R or B)

But we cannot calculate this with out knowing P(R) and P(B).

Hence answer is E.





siddhans wrote:
From st 1 we get : probability of selecting 1 red = 1/5 --- Insufficient

From st 2 we get: probability of selecting 1 blue = 1/3 ---- Insufficient

Combining 1 and 2 we get =>

Probability of 1 red or 1 blue = 1/5 + 1/3

Probability of green = 1 - (1/5 + 1/3)



Hence should be C... What wrong with this logic ...Can someone explain the flaw?


If there are 5 red eggs doesnt probability of selecting one red ball out of 5 be 1/5?
User avatar
Senior Manager
Senior Manager
Joined: 01 Feb 2011
Posts: 309
Own Kudos [?]: 324 [1]
Given Kudos: 42
Send PM
Re: Each of the eggs in a bowl is dyed red, or green, or blue. If one egg [#permalink]
1
Kudos
No. You are not selecting 1 ball out of 5 red balls.

Here we are talking about probability of with drawing 1 red ball out of n balls out of which lets say R are red.

probability = possible out comes/ total out comes

P(R=1) = Rc1/nc1


if you were to select 1 red ball out of 5 red balls then P(R=1) = 1/5.

siddhans wrote:
Spidy001 wrote:
P(R) is not 1/5.

P(R) = R/(total)

Given that there are 5 Red . But we don't know the total . so we cannot calculate P(R) without knowing total.


1. Not sufficient
R=5
when G = 2 , B = 1 => P(G) = 2/8
when G=1, B=2 => P(G) = 1/8

2. Not Sufficient

P(B) = 1/3 = x/3x

But this doesn't tell us anything about B or total because P(B) = 1/3 , but it could also be 2/6 or 3/9 so on..

So we can have different B . Thus we can have different G combinations.

Together - Not Sufficient

P(B) = x/(3x) , R = 5

P(G) = 1- P( not G )

= 1- P(R or B)

But we cannot calculate this with out knowing P(R) and P(B).

Hence answer is E.





siddhans wrote:
From st 1 we get : probability of selecting 1 red = 1/5 --- Insufficient

From st 2 we get: probability of selecting 1 blue = 1/3 ---- Insufficient

Combining 1 and 2 we get =>

Probability of 1 red or 1 blue = 1/5 + 1/3

Probability of green = 1 - (1/5 + 1/3)



Hence should be C... What wrong with this logic ...Can someone explain the flaw?


If there are 5 red eggs doesnt probability of selecting one red ball out of 5 be 1/5?
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6821
Own Kudos [?]: 29917 [1]
Given Kudos: 799
Location: Canada
Send PM
Re: Each of the eggs in a bowl is dyed red, or green, or blue. If one egg [#permalink]
1
Kudos
Expert Reply
Top Contributor
Lolaergasheva wrote:
Each of the eggs in a bowl is dyed red, or green, or blue. If one egg is to be removed at random. what is the probability that the egg will be green?

(1) There are 5 red eggs in the bowl.
(2) The probability that the egg will be blue is 1/3


Target question: What is the probability that the egg will be green?
Upon scanning the two statements, it certainly seems like there isn't enough information (each statement mentions just 1 color, and neither statement mentions green eggs)
As such, we can probably head straight to....
.
.
.
Statements 1 and 2 combined
There are several scenarios that satisfy BOTH statements. Here are two:
Case a: There are 5 red eggs, 1 green egg and 3 blue eggs (notice that both statements are satisfied). In this case, the answer to the target question is P(select green egg) = 1/9
Case b: There are 5 red eggs, 3 green egg and 4 blue eggs (notice that both statements are satisfied). In this case, the answer to the target question is P(select green egg) = 3/12 = 1/4
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E

Cheers,
Brent
Manager
Manager
Joined: 06 Jan 2017
Posts: 94
Own Kudos [?]: 108 [0]
Given Kudos: 283
Location: India
Concentration: General Management, Finance
GPA: 3.33
Send PM
Re: Each of the eggs in a bowl is dyed red, or green, or blue. If one egg [#permalink]
Lolaergasheva wrote:
Each of the eggs in a bowl is dyed red, or green, or blue. If one egg is to be removed at random. what is the probability that the egg will be green?

(1) There are 5 red eggs in the bowl.
(2) The probability that the egg will be blue is 1/3


Probability (green egg drawn) = # favorable events of drawing a green egg / #total no. of elementary events or sample space

P(GE) = n (green eggs)/N (total eggs)

Therefore, to calculate P(GE), we need values for both

'n' = total no. of green eggs and
'N' = total no. of eggs

Statement 1: Only gives us total no. of red eggs. Can't calculate P (GE) using this value.
REJECT A, D

Statement 2: Gives value of P (BE) i.e. probability of a blue egg drawn. This also can't help us in calculating P(GE)
REJECT B

Statement 1 & 2 together: This neither gives us value of 'n' and 'N'
Reject D

Correct option - E
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32658
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: Each of the eggs in a bowl is dyed red, or green, or blue. If one egg [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: Each of the eggs in a bowl is dyed red, or green, or blue. If one egg [#permalink]
Moderator:
Math Expert
92900 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne