Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Danny has boxes colored either red or blue. In each blue box [#permalink]
29 May 2012, 07:17

5

This post received KUDOS

4

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

58% (04:24) correct
42% (01:38) wrong based on 100 sessions

Danny has boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25, and the difference between the total number of strawberries and the total number of blueberries would increase by 95. Each blue box contains how many blueberries?

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
29 May 2012, 10:40

8

This post received KUDOS

2

This post was BOOKMARKED

Let b be the number of blue boxes and r the number of red boxes. Let x be the number of blueberries and y the number of strawberries in each blue and red box respectively.

If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25 => (b-1)x + (r+1)y = bx + ry + 25 => y - x = 25 [Eqn 1]

If Danny disposed of one blue box for one additional red box, the difference between the total number of strawberries and the total number of blueberries would increase by 95 => (r+1)y - (b-1)x = ry - bx + 95 => y + x = 95 [Eqn 2]

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
29 May 2012, 10:48

6

This post received KUDOS

Here is another way to solve this question: Replacing one blue box with a red box causes an increase of 25 berries overall => There are 25 more strawberries in a red box than blueberries in a blue box

Replacing one blue box with a red box causes the difference between the total number of strawberries and blueberries to increase by 95 => If there are x blueberries in a box, then we have taken away x blueberries, and replaced them by x+25 strawberries (using the statement above). By doing this, we have caused the difference between the remaining blueberries and strawberries to increase by x (blueberries removed) + x+25 (strawberries added) => x + x + 25 = 95 => x = 35 or choice A _________________

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
01 Jun 2012, 02:10

GyanOne wrote:

Let b be the number of blue boxes and r the number of red boxes. Let x be the number of blueberries and y the number of strawberries in each blue and red box respectively.

If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25 => (b-1)x + (r+1)y = bx + ry + 25 => y - x = 25 [Eqn 1]

If Danny disposed of one blue box for one additional red box, the difference between the total number of strawberries and the total number of blueberries would increase by 95 => (r+1)y - (b-1)x = ry - bx + 95 => y + x = 95 [Eqn 2]

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
02 Oct 2012, 07:25

GyanOne wrote:

Here is another way to solve this question: Replacing one blue box with a red box causes an increase of 25 berries overall => There are 25 more strawberries in a red box than blueberries in a blue box

Replacing one blue box with a red box causes the difference between the total number of strawberries and blueberries to increase by 95 => If there are x blueberries in a box, then we have taken away x blueberries, and replaced them by x+25 strawberries (using the statement above). By doing this, we have caused the difference between the remaining blueberries and strawberries to increase by x (blueberries removed) + x+25 (strawberries added) => x + x + 25 = 95 => x = 35 or choice A

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
02 Oct 2012, 11:57

@Gyanone - This statement is confusing "Replacing one blue box with a red box causes an increase of 25 berries overall => There are 25 more strawberries in a red box than blueberries in a blue box"

The problem only states that blueberries are fixed in the blue box but they still exist in the redbox. The increase in 25 is a combination of blueberries and redberries. It is not 25 redberries more.

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
03 Oct 2012, 00:36

vsprakash2003 wrote:

@Gyanone - This statement is confusing "Replacing one blue box with a red box causes an increase of 25 berries overall => There are 25 more strawberries in a red box than blueberries in a blue box"

The problem only states that blueberries are fixed in the blue box but they still exist in the redbox. The increase in 25 is a combination of blueberries and redberries. It is not 25 redberries more.

by replacing one blue box for one red box...increase it by 25..that means..red box contains more strawberries thats it increase by 25.. rather assume if both wud b same..how cud it b increased by 25 by replacing one blue box for red..

thats y we assume from the statement that red contains 25 more straw berries. _________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
21 Oct 2013, 10:37

Joy111 wrote:

Danny has boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25, and the difference between the total number of strawberries and the total number of blueberries would increase by 95. Each blue box contains how many blueberries?

A. 35 B. 40 C. 45 D. 50 E. 60

I solved it with reverse PI process.

Say

R | B | 70| 45

Let both boxes are 1 each. After I remove blue box, no of berries - 140 (25 more than initial sum) Now the diff as per qs should be 95. Let's see, The Initial diff = (70-45=25) Final diff = (140) Diff - 140-25 = 115. We need less diff, so,

R | B | 60| 35

Let both boxes are 1 each. After I remove blue box, no of berries - 120 (25 more than initial sum) Now the diff as per qs should be 95. Let's see,

Initial diff = (60-45=25) Final diff = (120-0= 120) Diff - 120-25 = 95. This matches the question stem, so, it's my answer.

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
18 Nov 2013, 15:54

Oh this is an interesting one!

The new box brought in 25 [more] Straw berries. The difference between the two increased 95 more [meaning that Straw Berries > Blue Berries, and not the other way around] Now to explain the Increase of 95; 25 came from the exchange of boxes, and we are left with 70 more straw berries.

{Now if you remember how elections work, Candidate A has 24 votes, Candidate B has 18 votes, but if three people turn from A to B than A will have 21 votes and B will have 21 votes. So in actuality Candidate A has only three votes lead (but whose effect is double or equal to Six votes).}

Okay back to the 70 straw berries, all we need to do is to divide the 70 by 2 (to cover up for the double effect) we get 35 or Answer choice A.

Re: Danny has boxes colored either red or blue. In each blue box [#permalink]
28 Nov 2014, 17:27

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...