Joy111 wrote:
Danny has boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25, and the difference between the total number of strawberries and the total number of blueberries would increase by 95. Each blue box contains how many blueberries?
A. 35
B. 40
C. 45
D. 50
E. 60
I solved it with reverse PI process.
Say
R  B

70 45
Let both boxes are 1 each.
After I remove blue box, no of berries  140 (25 more than initial sum)
Now the diff as per qs should be 95. Let's see,
The
Initial diff = (7045=25)
Final diff = (140)
Diff  14025 = 115. We need less diff, so,
R  B

60 35
Let both boxes are 1 each.
After I remove blue box, no of berries  120 (25 more than initial sum)
Now the diff as per qs should be 95. Let's see,
Initial diff = (6045=25)
Final diff = (1200= 120)
Diff  12025 = 95.
This matches the question stem, so, it's my answer.