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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
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Hi Engr2012,

Thanks for catching the error - there was one typo in the prompt. It's since been fixed.

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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
1
Kudos
If |a – b| = 6 and |b – c| = 15, then what is the value of |c|?

(1) |a – c| = 9
(2) |b| = 9

IMO E is correct

I]|a-c|= 9
this doesn't give any value for |c|

II] |b|=9
gives two different values for C

Joining I] and II]

doesn't reveal any unique value

SO E is correct
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
EMPOWERgmatRichC wrote:
QUANT 4-PACK SERIES Data Sufficiency Pack 3 Question 4 If |a - b| = 6...

If |a – b| = 6 and |b – c| = 15, then what is the value of |c|?

(1) |a – c| = 9
(2) |b| = 9


48 Hour Window Answer & Explanation Window
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OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

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EMPOWERgmatRichC thank you for updating the question.

As for the question, this question uses the definition of the absolute values ---> distance between 2 variables.

Given, |a – b| = 6 and |b – c| = 15 ---> distance between a and b is 6 units , while the distance between b and c is 15 units. Clearly if you are given the distance between a and c as 9 units, it will be sufficient to answer for |c| or distance of c from the 'zero' on the number line.

Statement 1 gives you that exact statement making it sufficient. |a-c| + |a-b| = |b-c| and from this relation you can get a unique 'distance' value of c , thus giving you a unique value of |c|.

Statement 2 does not give any new information for |c|. Not sufficient.

A is the correct answer.
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
EMPOWERgmatRichC wrote:
QUANT 4-PACK SERIES Data Sufficiency Pack 3 Question 4 If |a - b| = 6...

If |a – b| = 6 and |b – c| = 15, then what is the value of |c|?

(1) |a – c| = 9
(2) |b| = 9


48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

Scroll Down For Official Explanation


Hi Rich,
Really good question. Can you please detail your way in answering this question?Is Algebra only way to solve it? Using Test IT could not help me? I reached the answer A only as there are 3 variables with 3 equations but I could not prove it because I do not know how to solve 3 equations under modulus.
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
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Engr2012 wrote:
EMPOWERgmatRichC wrote:
QUANT 4-PACK SERIES Data Sufficiency Pack 3 Question 4 If |a - b| = 6...

If |a – b| = 6 and |b – c| = 15, then what is the value of |c|?

(1) |a – c| = 9
(2) |b| = 9


48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

Scroll Down For Official Explanation


EMPOWERgmatRichC thank you for updating the question.

As for the question, this question uses the definition of the absolute values ---> distance between 2 variables.

Given, |a – b| = 6 and |b – c| = 15 ---> distance between a and b is 6 units , while the distance between b and c is 15 units. Clearly if you are given the distance between a and c as 9 units, it will be sufficient to answer for |c| or distance of c from the 'zero' on the number line.

Statement 1 gives you that exact statement making it sufficient. |a-c| + |a-b| = |b-c| and from this relation you can get a unique 'distance' value of c , thus giving you a unique value of |c|.

Statement 2 does not give any new information for |c|. Not sufficient.

A is the correct answer.



Hi Engr2012,

Even I worked on the question on the similar way
considering these values on number line
But Statement 1 only provides value /magnitude of difference among these three points , but none provides value for the exact point.

As you mentioned it would be sufficient to answer for |c| or distance of c from the 'zero' on the number line.

But where does zero exist or reference of points in terms of zero is unknown.

ITS statement B which provides that |B|=9
thats also provides us with two options of value of B as 9 or -9
according to which value of C changes

Thats why I picked E

Please let me know flaw in my reasoning
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
Hi Rich,
Thanks for detailing your explanation. I have come with a question. What is the fact or condition which could be added to make the solution sufficient? It will help see how the variation of the question can happen.

Thanks
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
Mo2men wrote:
Hi Rich,
Thanks for detailing your explanation. I have come with a question. What is the fact or condition which could be added to make the solution sufficient? It will help see how the variation of the question can happen.

Thanks


1 way will be to have b=9 instead of |b|=9 for statement 2, and for statement 1, you can eliminate some cases by adding the fact that a and/or c have to be >0 etc. Many different ways to make the statements sufficient on their own and even when combined.

EMPOWERgmatRichC , thank you for the solution. Statement 1 is not sufficient. I interpreted the sufficiency incorrectly above. Statement 1 and the question stem mention the same thing, making this statement not sufficient.
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
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Very nice question.

\(|a-b|=6\)
\(|b-c|=15\) or \(|c-b|=15\)

On the real line:

\(c---------a------b------a---------c\)

each - represents 1 unit

(1) |a-c|=9. This is just repeating the above. Can't help answering the question (otherwise this would not be a DS...). Don't need even to consider letter C, its B or E.

(2)

if b=-9 then \((c=-24)----------(a=-15)------(b=-9)------(a=-3)---------(c=6)\)

if b=9 then \((c=-6)----------(a=3)------(b=9)------(a=15)---------(c=24)\)

|c| has two values 6 or 24 , insufficient. Letter E
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If |a – b| = 6 and |b – c| = 15, then what is the value of |c|?

(1) |a – c| = 9
(2) |b| = 9

There are 3 variables (a,b,c) and 2 equations (|a – b| = 6 and |b – c| = 15), so we need one more equation. There are 2 equations given from the 2 conditions, so there is high chance (D) will be our answer.
From condition 1, a-b=-6, 6/ b-c=-15, 15/ a-c=-9,9. There are too many possible answers, so this is insufficient.
From condition 2, a-b=-6, 6/ b-c=-15, 15/ b=-9,9; this is insufficient for the same reason
Looking at them together, c=-24, a=-15, b=-9 or c=-6, a=3, b=9. This also gives no unique answer,so this is insufficient as well.

For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
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Responding to a PM.

If we can visualise these points on a line, it becomes an easy question.

If |a – b| = 6 and |b – c| = 15, then what is the value of |c|?
So a is 6 units away from b, which in turn is 15 units away from c.
Two cases
a) …….a…..b…..c OR …….c……b…..a: In this case, a and c will be 6+15 or 21 units away
b) …….c…..a…..b OR …….b……a…..c: In this case, a and c will be 15-6 or 9 units away
We are looking for the value of |c|

(1) |a – c| = 9
This just confirms one of the above cases, that is case (b), but we do not know the location of c on the number line.
Nothing to move ahead.
Insufficient

(2) |b| = 9
When b=9: |b-c|=15….|9-c|=15……c could be 24 or -6
When b=-9: |b-c|=15….|-9-c|=15……c could be -24 or 6
So |c| could be 24 or 6.
Insufficient


Combined
Nothing new added to statement II when combined with statement I.
Let us see
|a-c|=9
Case I: ……c……a…….9 or …..-6……3……9 => |c|=6
Case II: ……9……a…….c or …..9……15……24 => |c|=24
Insufficient


E

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Re: Data Sufficiency Pack 3, Question 4 If |a - b| = 6... [#permalink]
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