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David has d books, which is 3 times as many as Jeff and 1/2

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David has d books, which is 3 times as many as Jeff and 1/2 [#permalink]  13 Dec 2012, 08:56
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David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d
[Reveal] Spoiler: OA
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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink]  13 Dec 2012, 08:58
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David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d

David has d books;
Jeff has d/3 books;
Paula has 2d books;

Total = d+d/3+2d=10d/3.

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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink]  10 Jan 2014, 01:11
David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d

We are given: [(d/3) = J] and [(d/2) = P], and we also have Davids own books = d

Just add all three together and express them in common denominator of 3: (3/3)*d + (d/3) + (6/3)*d = (10/3)*d
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Concentration: Finance, Entrepreneurship
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Kudos [?]: 84 [0], given: 200

Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink]  11 Jun 2014, 04:58
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It's also possible to solve with smart numbers
David has 120
Jeff 120/3 = 40
Paula 120*2 = 240
Total 400 Books --> 400/120 = 10/3
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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink]  12 Sep 2014, 05:30
David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d

David = d ; jeff=f ; paula = p

d=3j ; d=p(1/2)

d+j+p = d+ d/3 + 2d = 10d /3
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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink]  30 Sep 2014, 21:11
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David ................ Jeff ................... Paula

d ........................ $$\frac{d}{3}$$ ....................... 2d

$$Total = 3d + \frac{d}{3} = \frac{10d}{3}$$

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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink]  04 Oct 2015, 00:47
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Re: David has d books, which is 3 times as many as Jeff and 1/2   [#permalink] 04 Oct 2015, 00:47
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