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David has d books, which is 3 times as many as Jeff and 1/2

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David has d books, which is 3 times as many as Jeff and 1/2 [#permalink] New post 13 Dec 2012, 08:56
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David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d
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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink] New post 13 Dec 2012, 08:58
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Walkabout wrote:
David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d


David has d books;
Jeff has d/3 books;
Paula has 2d books;

Total = d+d/3+2d=10d/3.

Answer: C.
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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink] New post 10 Jan 2014, 01:11
Walkabout wrote:
David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d



We are given: [(d/3) = J] and [(d/2) = P], and we also have Davids own books = d


Just add all three together and express them in common denominator of 3: (3/3)*d + (d/3) + (6/3)*d = (10/3)*d
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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink] New post 11 Jun 2014, 04:58
It's also possible to solve with smart numbers
David has 120
Jeff 120/3 = 40
Paula 120*2 = 240
Total 400 Books --> 400/120 = 10/3
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Re: David has d books, which is 3 times as many as Jeff and 1/2 [#permalink] New post 12 Sep 2014, 05:30
Walkabout wrote:
David has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?

(A) 5/6*d
(B) 7/3*d
(C) 10/3*d
(D) 7/2*d
(E) 9/2*d




David = d ; jeff=f ; paula = p


d=3j ; d=p(1/2)

d+j+p = d+ d/3 + 2d = 10d /3
Re: David has d books, which is 3 times as many as Jeff and 1/2   [#permalink] 12 Sep 2014, 05:30
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