ugimba wrote:

Did one of the 3 members of a certain team sell atleast 2 raffle tickets yesterday?

1) The 3 members sold a total of 6 raffle tickets yesterday.

2) No 2 of the members sold the same number of raffle tickets yesterday.

From F.S 1, we have the total no of raffles being sold as 6. The average no of raffles sold per person would be 6/3 = 2. Thus, any combination between these three people will end up with one person getting more than 2 or at-least 2 raffles. For example, (2,2,2);(0,4,2);(1,1,4) etc. Sufficient.

From F.S 2, we have the no of tickets sold by each is different in value. Assuming that all three of them sold 0 tickets is thus not possible. If one person sold zero tickets, the second person will have to sell 1 or any no. more than that. Similarly, for the third person. Thus, one of the member would have atleast sold atleast 2 raffle tickets. Sufficient.

D.

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