Find all School-related info fast with the new School-Specific MBA Forum

It is currently 03 Aug 2015, 20:24
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

disagree with OA

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Senior Manager
Senior Manager
avatar
Joined: 02 Feb 2004
Posts: 345
Followers: 1

Kudos [?]: 30 [0], given: 0

disagree with OA [#permalink] New post 19 Jul 2005, 18:18
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

disagree with OA
Attachments

0001.jpg
0001.jpg [ 3.26 KiB | Viewed 486 times ]

VP
VP
User avatar
Joined: 14 Feb 2005
Posts: 1001
Location: New York
Followers: 5

Kudos [?]: 17 [0], given: 0

 [#permalink] New post 19 Jul 2005, 19:56
1. X is an integer ..Nothing can be said

2.X2 < 1 ..Possible only when X is between 0 -1 or x = 0

In either of the case mod{x-6} is always greater than 5 ..

So Answer is B...correct me if i am wrong

Cheers
Manager
Manager
User avatar
Joined: 21 Jun 2004
Posts: 239
Followers: 1

Kudos [?]: 2 [0], given: 0

 [#permalink] New post 20 Jul 2005, 08:51
although B stands - i would say that the value of x can lie between -1 and 1 ( exclusive of those values)....

Quote:
Ozmba2006
Active Member



Joined: 14 Feb 2005
Posts: 33

Posted: Tue Jul 19, 2005 7:56 pm Post subject:

--------------------------------------------------------------------------------

1. X is an integer ..Nothing can be said

2.X2 < 1 ..Possible only when X is between 0 -1 or x = 0

In either of the case mod{x-6} is always greater than 5 ..

So Answer is B...correct me if i am wrong

Cheers
Senior Manager
Senior Manager
avatar
Joined: 30 May 2005
Posts: 277
Followers: 1

Kudos [?]: 11 [0], given: 0

 [#permalink] New post 20 Jul 2005, 15:46
plz what is the OA
I agree that st 1 NOT SUFFICIENT


ST2
x^2 <1
x<sq root of 1
x<- sq root of 1
hence x<-1
x <+1
then i am stuck
can anyone correct me thanks
Current Student
avatar
Joined: 28 Dec 2004
Posts: 3387
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 14

Kudos [?]: 192 [0], given: 2

 [#permalink] New post 21 Jul 2005, 08:11
Hey

this is B....


|x-6| >5?

1) x is an integer than x=4

|4-6|=2 which is <5

x can be 20

|20-6|= 14 which is > 5

insuff

2)

X^2<1

then X is a fraction

say X is 1/2

|1/2-6| = 5.5 which is >5

or X could be 0

|0-6| = 6 which is > 5...

so either way we can that (2) is always sufficient...it is always >5

B it is...
Senior Manager
Senior Manager
avatar
Joined: 04 May 2005
Posts: 284
Location: CA, USA
Followers: 1

Kudos [?]: 24 [0], given: 0

 [#permalink] New post 21 Jul 2005, 20:05
B

x>11 or x<1

with x^2 < 1, for sure x < 1
Senior Manager
Senior Manager
avatar
Joined: 17 Apr 2005
Posts: 375
Location: India
Followers: 1

Kudos [?]: 18 [0], given: 0

 [#permalink] New post 22 Jul 2005, 06:06
mandy wrote:
plz what is the OA
I agree that st 1 NOT SUFFICIENT


ST2
x^2 <1
x<sq root of 1
x<- sq root of 1
hence x<-1
x <+1
then i am stuck
can anyone correct me thanks


so x should be b/w -1 and 1.
Then for any such value | x - 5 | > 6

HMTG.
SVP
SVP
User avatar
Joined: 05 Apr 2005
Posts: 1731
Followers: 5

Kudos [?]: 40 [0], given: 0

Re: inequalities [#permalink] New post 22 Jul 2005, 19:17
mirhaque wrote:
disagree with OA


However, i answerd B as the OA, the question is poorly worded. suppose if statement ii is not sufficient to answer the question, statements i and ii jointly cannot answer the question because these statement contradict each other.
Re: inequalities   [#permalink] 22 Jul 2005, 19:17
Display posts from previous: Sort by

disagree with OA

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.