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distance (m03q28)

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Re: distance (m03q28) [#permalink] New post 03 Oct 2012, 06:04
I have a question.. aren't these two going TOWARDS each other? The answer is still the same regardless.. but I don't think it holds true all the time.

If they were going in the same direction, you would equate their distance equations (rate*time). But they're meeting up from opposite directions.. so they're closing into each other. here is how I would set up the equation..

The distance travelend by the 2 should equal 48.
Let t=Walt's time

4(t+2)+6t=48
4t+8+6t=48
10t=40
t=4
Answer is 24 miles

If the started at the same time (had the same time value), I would just subtrance one rate from the other and equate the distance to 0 (dimishing distanc ebetween them set at 0). But since they didn't, I couldn't do that.


Can someone tell me if my logic above is incorrect?

Last edited by chris558 on 03 Oct 2012, 07:20, edited 1 time in total.
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Re: distance (m03q28) [#permalink] New post 03 Oct 2012, 06:18
Expert's post
chris558 wrote:
I have a question.. aren't these two going in OPPOSITE directions? The answer is still the same regardless.. but I don't think it holds true all the time.

If they were going in the same direction, you would equate their distance equations (rate*time). But they're meeting up from opposite directions.. so they're going in opposite directions so here is how I would set up the equation..

The distance travelend by the 2 should equal 48.
Let t=Walt's time

4(t+2)+6t=48
4t+8+6t=48
10t=40
t=4
Answer is 24 miles

If the started at the same time (had the same time value), I would just subtrance one rate from the other and equate the distance to 0 (dimishing distanc ebetween them set at 0). But since they didn't, I couldn't do that.


Can someone tell me if my logic above is incorrect?


The question states that "Lionel left his house and walked towards Walt's house ... Walt left his house and ran towards Lionel's house", so they are moving towards each other.

Check the solution here: distance-m03q28-59171.html#p1127472

Hope it helps.
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Re: distance (m03q28) [#permalink] New post 03 Oct 2012, 06:31
@chris, in GMAT the language is factor which makes the quants more interesting , never miss any single point.

Also,We should recheck the answer using a little non-mechanical calculation as described by Bunuel . In GMAT one should always know more than one method to solve any quants question.
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Re: distance (m03q28) [#permalink] New post 03 Oct 2012, 07:23
Bunuel wrote:
The question states that "Lionel left his house and walked towards Walt's house ... Walt left his house and ran towards Lionel's house", so they are moving towards each other.

Check the solution here: distance-m03q28-59171.html#p1127472

Hope it helps.


Whoops- that's what I meant (I edited my post). A lot of people solved this by setting up the two rate equations to equal one another which gave the right answer, but only in this case. That should be done only if they were moving in the same direction. Because they're closing in on one another, I would've just solved it the way I previously explained (or the way you did in your other post).
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Re: distance (m03q28) [#permalink] New post 02 Oct 2013, 05:03
I think I may have done this wrong but got the correct answer.
Lionel initially starts at 2*4=8 so
Lionel's distance is 8+4t
Walt's distance is 6t
I set them equal to each other to see when they met. 8+4t=6t; so 8=2t and t=4
I plug 4 back to Lionel's distance equation 8+4(4)=24 so answer D

I never used the 48 miles given in the question like other people, is my method wrong?
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Re: distance (m03q28) [#permalink] New post 02 Oct 2013, 07:47
Expert's post
wgtaylor wrote:
I think I may have done this wrong but got the correct answer.
Lionel initially starts at 2*4=8 so
Lionel's distance is 8+4t
Walt's distance is 6t
I set them equal to each other to see when they met. 8+4t=6t; so 8=2t and t=4
I plug 4 back to Lionel's distance equation 8+4(4)=24 so answer D

I never used the 48 miles given in the question like other people, is my method wrong?


Yes, it is wrong.

We don't know whether they meet at halfway of 48-mile distance, thus you cannot equate 8+4t and 6t.

Check for a solution here: distance-m03q28-59171.html#p1127472
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PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: distance (m03q28) [#permalink] New post 03 Oct 2013, 05:20
Lionel walks 8 miles before Walt starts walking (2hrs @ 4mph)
Together they have to "manage" 40 mile distance. While we could use combined rate to figure the time both spent, it is not necessary (though it would be 4 hours). Since the rates of the speeds are in the ratio of 2:3, Lionel walks 40% of the distance (and Walt 60%), or 40miles*40%=16 miles.

16+8 = 24 --> total miles Lioned walked.
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Re: distance (m03q28)   [#permalink] 03 Oct 2013, 05:20
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