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Distance travelled [#permalink]
28 Mar 2011, 07:32
100% (02:44) correct
0% (00:00) wrong based on 1 sessions
If a motorist had driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day?
Re: Distance travelled [#permalink]
28 Mar 2011, 08:02
Let v and t be initial parameter vt=d from the stem (t+1)(v+5)=70+d =>v+5t=65-------1)
We need the additional distance traveled second time at v+10 and t+2 (t+2)(v+10)=vt+2v+10t+20 but vt=d Hence d+2(v+5t)+20 But v+5t=65 hence the additional distance traveled is 2(v+5t)+20=2*65+20=130+20=150