This is bothering the hell out of me. I know that if the last two digits of a number added together are divisible by 4 then the number is divisible by 4. In addition if a number is divisible by 3 and 4 then it is divisible by 12. I also know from simple math that 96 is divisible by all 3. However, when you add 9 + 6 you get 15. A number not divisible by 4. Is 96 just an exception to this rule, or are there more loop holes in other places as well? Thank you.
The red part is not correct. The number is divisible by 4 if the last two digits form a number divisible by 4.
Sum of the digits rule work only for 3 and 9:
3 - If the sum of the digits is divisible by 3, the number is also.
9 - If the sum of the digits is divisible by 9, so is the number.
For more check on number theory and divisibility check: math-number-theory-88376.html
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