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divisibility

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divisibility [#permalink] New post 11 Jul 2011, 07:05
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Question Stats:

83% (01:12) correct 16% (01:35) wrong based on 0 sessions
hey,

In the book it says follow [spoiler].12y=9[/spoiler] but I want to ask you experts whether my way is ok too:

x/y = 96.12 --> .12(100) --> 12/100 --> 3/25

So the remainder is 3 or a multiple of 3 and the divisor is 25 or a multiple of 25.

Since the questions says the remainder is 9 which is 3 times the remainder I got from the above fraction (3/25) I would have to multiply 25 by 3 as well to get what y equals which is [spoiler]75. Hence the right answer. But is my method ok?[/spoiler]



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Re: divisibility [#permalink] New post 12 Jul 2011, 01:09
well....
you can say that z/y= 96 + (12/100)
12/100= 3/25
so y must be 25 or multiple of 25 :D
and only 75 is multiple of 25 so you don't need to do the multiplication process
best wishes on your prep.
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Re: divisibility   [#permalink] 12 Jul 2011, 01:09
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