Can any one explain how to find the ans. to these kind of questions:
I do not have the OA or OE
When a number N is divided by d1, the remainder is r1. When this number is divided by d2, the remainder is r2. What is the remainder when this number is divided by d1d2.
i digged someting here: http://www.gmatclub.com/phpbb/viewtopic.php?t=17675
go to the attachments, banerjee managed to have something, though i couldnot proved his method/formula.
i believe, honghu should have better idea.
Thanks Professor, for researching and finding the link.
....but this example has got me even more confused.
Here is the text:
When a number is successively divided by two divisors d1 and d2 and two remainders r1 and r2 are obtained, the remainder that will be obtained by the product of d1 and d2 is given by the relation d1r2 + r1.
Where d1 and d2 are in ascending order respectively and r1 and r2 are their respective remainders when they divide the number.
In this case, the d1 = 8 and d2 = 11. And r1 = 3 and r2 = 7. Therefore, d1r2 + r1 = 8*7 + 3 = 59.
........in this example, if you try to do the reverse starting with 59 dividing it by either 8 or 11 whichever way, I don't see how you can get an r2=7
....I think I need some serious therapy now!!!