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Do j and k yield the same remainder when divided by 24? (1)

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Do j and k yield the same remainder when divided by 24? (1) [#permalink] New post 14 Jul 2006, 02:46
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C
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Do j and k yield the same remainder when divided by 24?

(1) When j and k are divided by 8 , they yield the same remainder.
(2) If j´=j/4.5 and k´=k/4.5, j´-k´is an even integer.
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 [#permalink] New post 14 Jul 2006, 04:46
Each statement alone is not sufficient.

(1) for example j=8, k= 0 or j=24 k=0.

(2) for example j=9, k=0 or j=72 k=0

Both statements together?

From (2) we know that (2j - 2k)/9 = even integer
Therefore j=k+9 or j=k-9.

Using (1), we can derive that the distance between j and k must be k*8 (k integer). Putting (1) and (2) together we get, that there distance must be k*72 (k integer) (and some other irrelevant conditions, because of (2)).
Therefore, the remainder must be the same, when we divide by 24.

Hence C.
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Re: DS: same remainder (corrected) [#permalink] New post 14 Jul 2006, 07:31
kevincan wrote:
Do j and k yield the same remainder when divided by 24?

(1) When j and k are divided by 8 , they yield the same remainder.
(2) If j´=j/4.5 and k´=k/4.5, j´-k´is an even integer.


C

St1: j = (A = Multiple of 8) + x and k = (B = Multiple of 8) + x: May be true or false. A or B may be multiple of 24 or not. : INSUFF

St2: This means (j-k)/4.5 is an even integer i.e (j-k) is [4.5 * (Even Integer)] i.e either j = odd multiple of 4.5 and k = odd multiple of 4.5 OR j = even multiple of 4.5 and k = even multiple of 4.5.: INSUFF

Combined: We can say that j and K must be multiple of 72. So will yield same remainder
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Re: DS: same remainder (corrected)   [#permalink] 14 Jul 2006, 07:31
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Do j and k yield the same remainder when divided by 24? (1)

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