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Does 2m - 3n = 0 (1) m ≠ 0 (2) 6m = 9n

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Damouse
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Does 2m - 3n = 0 (1) m ≠ 0 (2) 6m = 9n [#permalink] New post   08 Nov 2011, 01:46
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Does 2m - 3n = 0

(1) m ≠ 0
(2) 6m = 9n

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The answer is B, but I don't understand why.

1. Can't you rewrite the above as 2m = 3n?

If M is...then N is
3 2
6 4
-3 -2
-6 -4

2. The explanation rewrites 2 as 3(2m = 3n) ad says Suff
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B
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Re: Does 2m - 3n = 0 (1) m ≠ 0 (2) 6m = 9n [#permalink] New post   08 Nov 2011, 02:49
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The question is not asking you to find possible values of (m,n). You are not required to do this at all. All you need to find out is whether 2m -3n = 0

Rewrite the question prompt as -
=> 2m = 3n
=> m/n = 3/2

Statement 1 - m != 0; This tells us nothing about 'n'. Insufficient.
Statement 2 - 6m = 9n => m/n = 3/2 ; The ratio m/n is same as that in the question prompt. Sufficient.

Ans. B
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Re: Does 2m - 3n = 0 (1) m ≠ 0 (2) 6m = 9n [#permalink] New post   08 Nov 2011, 03:40
Damouse wrote:
Does 2m - 3n = 0

1. m not = 0
2. 6m = 9n

The answer is B, but I don't understand why.

1. Can't you rewrite the above as 2m = 3n?

If M is...then N is
3 2
6 4
-3 -2
-6 -4

2. The explanation rewrites 2 as 3(2m = 3n) ad says Suff



The qn says is 2m-3n = 0?
You need to have the values or stat tht gives the result.

i) m is not 0 (may or may not make the stat true)
ii) 6m = 9n implies 2m = 3n so proves the stat 2m-3n = 0 and the stat is true.
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Re: Does 2m - 3n = 0 (1) m ≠ 0 (2) 6m = 9n [#permalink] New post   16 Feb 2012, 00:33
piyushpachori wrote:
The question is not asking you to find possible values of (m,n). You are not required to do this at all. All you need to find out is whether 2m -3n = 0

Rewrite the question prompt as -
=> 2m = 3n
=> m/n = 3/2

Statement 1 - m != 0; This tells us nothing about 'n'. Insufficient.
Statement 2 - 6m = 9n => m/n = 3/2 ; The ratio m/n is same as that in the question prompt. Sufficient.

Ans. B


I probably complicate myself but still wish to clarify if this can be E.

Since the question didn't indicate it is m & n are both INTEGER, so put fraction into considerations as well.
When I put in
m = 2, n = 3 or m = 1/2, n = 1/3, B comes valid...so isn't it a vague question? or I missed any important step? pls advise..thanks
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Re: Does 2m - 3n = 0 (1) m ≠ 0 (2) 6m = 9n [#permalink] New post   16 Feb 2012, 01:05
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miweekend wrote:
piyushpachori wrote:
The question is not asking you to find possible values of (m,n). You are not required to do this at all. All you need to find out is whether 2m -3n = 0

Rewrite the question prompt as -
=> 2m = 3n
=> m/n = 3/2

Statement 1 - m != 0; This tells us nothing about 'n'. Insufficient.
Statement 2 - 6m = 9n => m/n = 3/2 ; The ratio m/n is same as that in the question prompt. Sufficient.

Ans. B


I probably complicate myself but still wish to clarify if this can be E.

Since the question didn't indicate it is m & n are both INTEGER, so put fraction into considerations as well.
When I put in
m = 2, n = 3 or m = 1/2, n = 1/3, B comes valid...so isn't it a vague question? or I missed any important step? pls advise..thanks


You are right we are not told that m and n are integers, though we can get that statement (2) is sufficeint even not knowing that.

Does 2m - 3n = 0

Question basically asks whether \(2m=3n\)

(1) \(m\neq{0}\) --> clearly insufficient as no info about n.
(2) \(6m=9n\) --> reduce by 3: \(2m=3n\), so this statement directly answers the question (so here it doesn't matter whether m and n are integers). Sufficient.

Answer: B.

Hope it's clear.
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Re: Does 2m - 3n = 0 (1) m 0 (2) 6m = 9n [#permalink] New post   23 Nov 2023, 02:55
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Re: Does 2m - 3n = 0 (1) m 0 (2) 6m = 9n [#permalink]
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