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Re: Does anyone have a link where I can learn the theory to [#permalink]
jamesrwright3 wrote:
Does anyone have a link where I can learn the theory to solve these problems? I have never seen something like this before


(5^21)(2^22) = 2*(2*5)^n
(5^21)(2^22) = 2*(2^n)*(5^n)
(5^21)(2^22) = 2^(n+1)*(5^n)

Hence comparing exponents of Left hand side and righ hand side

n=21



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Re: Does anyone have a link where I can learn the theory to [#permalink]
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