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# Does anyone have a quick way of approaching this problem?

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Manager
Joined: 05 Feb 2007
Posts: 140
Followers: 1

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Does anyone have a quick way of approaching this problem?  [#permalink]

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15 May 2008, 20:02
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Does anyone have a quick way of approaching this problem?

The scores in a certain exam were 60, 75, 100, 70 and x. If the median score was 5 points lower then the average score on the exam, then what could x be?

A. 75
B. 80
C. 85
D. 90
E. 95
Senior Manager
Joined: 20 Feb 2008
Posts: 296
Location: Bangalore, India
Schools: R1:Cornell, Yale, NYU. R2: Haas, MIT, Ross
Followers: 4

Kudos [?]: 44 [0], given: 0

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15 May 2008, 20:11
Hi,
I think the answer is E 95

We have 5 numbers
60,70,75,100 and x

The median is either 70-75 depending on the value of x. Therefore the average is either 75 or 80,
if average =75
60+70+75+100+x =75*5; x=70 which is not an option

if average =80

x=400-305=95
Re: PS: median/average   [#permalink] 15 May 2008, 20:11
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