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Does anyone know a shortcut for this type of problems? I

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Manager
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Does anyone know a shortcut for this type of problems? I [#permalink] New post 01 May 2007, 10:38
Does anyone know a shortcut for this type of problems? I know how to solve them, but it takes me quite some time....
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 [#permalink] New post 01 May 2007, 15:42
No slick method. I toyed around w/it and got A.
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 [#permalink] New post 01 May 2007, 19:47
The Answer should be "E".but I dont see any other method other than putting numbers less than 10 foo the remaining ...
i.e 9+8+7+6+4 can make 75 even if one is 41...
so "A" can still be "9"
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 [#permalink] New post 04 May 2007, 10:50
Ans: E
(1) 41 Reps to the Congress. We have 34 remaining reps.
Given condition: A sends second largest number of reps.
So we can have something like 9, 8, 7, 6, 4 reps per country (no two countries sending the same no of reps), A being 9, so NOT SUFFICIENT

(2) For B to be the Ans, we should have Country A to send either 10 or 11 reps. But again,we can have something like 41, 9, 8, 7, 6, 4 (=75) 0r even 1,2,3,4,5 and 60 (A being 5). Hence NOT SUFFICIENT

(3) Putting these 2 together: 41 for B, say 9 for A (A < 12)... still you have choices to fill for the 4 countries. NOT SUFFICIENT.

Hence E. (This is my first post :barbarian )
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 [#permalink] New post 04 May 2007, 11:17
I used the same reasoning as menonsujith and got E.

What's the OA?
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 [#permalink] New post 04 May 2007, 12:13
I got A for an answer
  [#permalink] 04 May 2007, 12:13
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