Does anyone know how A is also correct here? I know that

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Does anyone know how A is also correct here? I know that [#permalink]

07 May 2011, 14:04

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Does anyone know how A is also correct here? I know that when triangles share the same base, one triangle is 2x the other with respect to the angle that is not common between them. I'm unable to see how angle QPS = RPS = 30 though.

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Re: DS Question, Geometry GMATPrep, Triangles [#permalink]

07 May 2011, 14:33

options 1 and 2 are essentially giving the same answer then very hight probability of D and E to be answers.

a. angle QPR = 30 means angle Q + QRP = 150
Q + (180 - SRP) = 150

gives angle SRP - Q = 30. Hence sufficient.

b essentially talks the same thing. the difference is 30.

thus D.
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Re: DS Question, Geometry GMATPrep, Triangles [#permalink]

08 May 2011, 08:21

PRS = PQR + QPR

(1)

PRS = PQR + 30

=> PRS - PQR = 30

Sufficient

(2)

QPR = 180 - 150 = 30

Again :
PRS = PQR + 30

=> PRS - PQR = 30
Sufficient

Answer - D
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Re: DS Question, Geometry GMATPrep, Triangles [#permalink]

08 May 2011, 17:30

PRS-PQR=?

1. Sufficient

QPR = 30
QPR+PQR+QRP = 180

=>30+PQR+180-PRS = 180
=> PRS-PQR can be found.

2. Sufficient

PQR+PRQ = 150
PQR+180-PRS = 150

Answer is D.

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Re: DS Question, Geometry GMATPrep, Triangles [#permalink]

09 May 2011, 00:03

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Here is my video solution.

http://www.gmatquantum.com/shared-posts ... tion1.html

Dabral
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Re: DS Question, Geometry GMATPrep, Triangles [#permalink] 09 May 2011, 00:03

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Does anyone know how A is also correct here? I know that

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Does anyone know how A is also correct here? I know that

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