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DOES ETS CONSIDER 0 AS POSITIVE INTEGER. [#permalink]
 21 Jul 2009, 22:32
Question Stats:
100% (07:33) correct
0% (00:00) wrong based on 1 sessions
Below is the list of questions for which it is to be confirmed whether 0 is a positive integer or not.
1.How many 4-digit positive integers are there in which all 4 digits are even?
A. 625
B. 600
C. 500
D. 400
E. 256
Answer:
2.If x and y are positive integers and y = 9 - x , what is the value of y?
(1) x < 8
(2) y > 1
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Answer:
Q15:
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22.
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Re: DOES ETS CONSIDER 0 AS POSITIVE INTEGER. [#permalink]
22 Jul 2009, 00:22
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Below is the list of questions for which it is to be confirmed whether 0 is a positive integer or not.
1.How many 4-digit positive integers are there in which all 4 digits are even?
A. 625
B. 600
C. 500
D. 400
E. 256
Answer:
Even numbers: 2,4,6,8
4 digit positive number with all even : 4X4X4X4 = 256
Should be E. BTW 0 is neither +ive nor -ive.
Maybe I am missing the context here. No offense but are you asking or telling about consideration for zero?
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Re: DOES ETS CONSIDER 0 AS POSITIVE INTEGER. [#permalink]
22 Jul 2009, 00:29
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Q15:
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22.
Sum of K,M,R,S,T = 80 (given mean is 16)
T = 40
Sum of K,M,R,S = 40. - (1)
k<M<R<S<T - (2)
To have the greatest median we need to have the Highest possible value of R keeping 1,2 in consideration.
Assign smallest possible values to K,M i.e. 1,2 (since K<M & both are positive int).
R+S = 40 - (K+M)=40-3 = 37
Highest value of R,S = 18,19 (honors R<S)
Hence median 18 - Which is (B)
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Re: DOES ETS CONSIDER 0 AS POSITIVE INTEGER. [#permalink]
22 Jul 2009, 00:31
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And E for
.If x and y are positive integers and y = 9 - x , what is the value of y?
(1) x < 8
(2) y > 1
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Answer:
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Senior Manager
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Re: DOES ETS CONSIDER 0 AS POSITIVE INTEGER. [#permalink]
20 Oct 2009, 12:24
irajeevsingh wrote: Below is the list of questions for which it is to be confirmed whether 0 is a positive integer or not.
1.How many 4-digit positive integers are there in which all 4 digits are even?
A. 625
B. 600
C. 500
D. 400
E. 256
Answer:
Even numbers: 2,4,6,8
4 digit positive number with all even : 4X4X4X4 = 256
Should be E. BTW 0 is neither +ive nor -ive.
Maybe I am missing the context here. No offense but are you asking or telling about consideration for zero? The requirement is that the integers be positive, not the digits, so 0 is ok. The first digit cannot be zero, because that makes it a 3 digit number. So answer C.
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Re: DOES ETS CONSIDER 0 AS POSITIVE INTEGER. [#permalink]
20 Oct 2009, 13:54
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0 is neither negative nor positive. Though it's even number. How many 4-digit positive integers are there in which all 4 digits are even? A. 625 B. 600 C. 500 D. 400 E. 256 Four digits: A, B, C, D. A can take 4 values - 2, 4, 6, 8. Zero is out, because otherwise we won't have 4 digit number and have three digit number. B, C, D can take 5 values - 0, 2, 4, 6, 8. Total=4*5^3=500 Answer: C 2.If x and y are positive integers and y = 9 - x , what is the value of y? (1) x < 8 (2) y > 1 First note that: y and x to be positive (y>0, x>0), 1<=y<=8 and 1<=x<=8 (y(max)=8 and y(min)=1>0, x(max)=8 and x(min)=1>0) (1) x<8 --> y=9-x(<8) --> y>2. Not sufficinet (2) y>1 --> Not sufficient (1)+(2) y>2, y>1 Not sufficient. Answer: E. The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers? A. 16 B. 18 C. 19 D. 20 E. 22. 0<k < m< r < s < t=40 --> we have 5 distinct, positive integers --> median=r (middle number) --> k+m+r+s+40=16*5=80 --> k+m+r+s=40 --> r to be max, k+m have to be min=1+2=3. --> r+s=37 --> r+s=37 --> r=18(max possible value) s=19 (they must be distinct and r<s) r(max)=18 Answer: B.
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Re: DOES ETS CONSIDER 0 AS POSITIVE INTEGER.
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20 Oct 2009, 13:54
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