Does p^2 = q if p is a prime number? (1) q^2 - P^2 = 0 (2) : DS Archive
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# Does p^2 = q if p is a prime number? (1) q^2 - P^2 = 0 (2)

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Does p^2 = q if p is a prime number? (1) q^2 - P^2 = 0 (2) [#permalink]

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04 Jun 2005, 16:43
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Does p^2 = q if p is a prime number?
(1) q^2 - P^2 = 0
(2) P^2 = 49
Director
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04 Jun 2005, 17:01
I wanted to put the same question. I got it wrong in the test....
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04 Jun 2005, 17:35
Vithal wrote:
Does p^2 = q if p is a prime number?
(1) q^2 - P^2 = 0
(2) P^2 = 49

i do not think it is so easy. anyway, let me try this way:

from i, q^2 - P^2 = 0,
q^2 = P^2.
so, q = + or - p.
if p = 0 or 1, the answer is yes, otherwise not. but the question says that p is a prime number. so q = +p. so sifficient.

from ii, it says only about the value of p which is 7. we do not have any relationship bet p and q. so it is insufficient to tell something about p and q.

so i go with A.
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04 Jun 2005, 18:16
C.

P isn't p

and A, if P is indeed p, a typo
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04 Jun 2005, 20:39
sparky wrote:
C. P isn't p. and A, if P is indeed p, a typo

in gmat, normally you donot have to face such an issue.
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05 Jun 2005, 10:39
it should be A

p = prime number

p^2 is then a perfect square!

I)p^2=q^2

P=q, then given that p is a prime number....therefore we know that (prime)^2 <> to q!

sufficient!

II) insuff....
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05 Jun 2005, 11:44
Vithal wrote:
Does p^2 = q if p is a prime number?
(1) q^2 - P^2 = 0
(2) P^2 = 49

A

as a tells you that tha q^2 = p^2 and the only possibility of that being true while p^2=q is if they were both 1. Since we know this is not the case, the statement 'p^2=q' is always false.

second statement gives no info
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05 Jun 2005, 12:40
(1) q^2 - P^2 = 0
q^2=p^2
p is prime so p<>1 and p<>0
=> q<>1 and q<>0
=> p^2 = q^2<>q
Sufficient

(2) P^2 = 49

(A)
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05 Jun 2005, 12:43
sparky wrote:
C.

P isn't p

If P is not p then q^2=49, q=+/-7.
p is a prime number, so p^2<>+/-7. Sufficient. Therefore C.
Good one sparky.
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05 Jun 2005, 12:43
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