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Does the decimal equivalent of P/Q, where P and Q are [#permalink]
 23 Jan 2010, 00:37
Question Stats:
86% (01:23) correct
13% (00:13) wrong based on 3 sessions
Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits? (1) P>Q (2) Q=8 Please explain
Last edited by Bunuel on 26 Jan 2012, 03:39, edited 1 time in total.
Edited the OA, it must be B not E
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vaivish1723 wrote: 26 Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits? (1) P>Q (2) Q=8 Please explain Oa is Reduced fraction \frac{a}{b} (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only b (denominator) is of the form 2^n5^m, where m and n are non-negative integers. For example: \frac{7}{250} is a terminating decimal 0.028, as 250 (denominator) equals to 2*5^2. Fraction \frac{3}{30} is also a terminating decimal, as \frac{3}{30}=\frac{1}{10} and denominator 10=2*5. Question: Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits? According to the above we must determine whether the denominator (after reducing the fraction, if possible) contains only the 2-s and/or 5-s as the prime factors. (1) P>Q, clearly insufficient. (2) Q=8=2^3, hence denominator has only 2 as prime factor. Fraction P/Q will be terminated decimal. Sufficient. Answer: B.
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why am I seeing all the questions with wrong OA today or atleast it seemed to be  I too got the ans as B
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Bunuel wrote: vaivish1723 wrote: 26 Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits? (1) P>Q (2) Q=8 Please explain Oa is (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only b (denominator) is of the form 2^n5^m, where m and n are non-negative integers. For example: \frac{7}{250} is a terminating decimal 0.028, as 250 (denominator) equals to 2*5^2. Fraction \frac{3}{30} is also a terminating decimal, as \frac{3}{30}=\frac{1}{10} and denominator 10=2*5. Question: Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits? According to the above we must determine whether the denominator (after reducing the fraction, if possible) contains only the 2-s and/or 5-s as the prime factors. (1) P>Q, clearly insufficient. (2) Q=8=2^3, hence denominator has only 2 as prime factor. Fraction P/Q will be terminated decimal. Sufficient. Answer: B. (OA must be wrong) Hello Bunuel How can we say that the fraction given is a "reduced fraction". Because if it's not than 70/8 is a non-terminating value.
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nverma wrote: Hello Bunuel
How can we say that the fraction given is a "reduced fraction". Because if it's not than 70/8 is a non-terminating value. Denominator already has only 2-s so in this case it's doesn't matter whether the fraction is reduced or not. For example \frac{x}{2^n5^m}, (where x, n and m are integers) will always be the terminating decimal. We need reducing in case when we have the prime in denominator other then 2 or 5 to see whether it could be reduced. For example fraction \frac{6}{15} has 3 as prime in denominator and we need to know if it can be reduced. Hope it's clear.
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Bunuel please excuse the stupid question but I'm quite weak in these types of questions.
* Does the rule basically say that any integer divided by either 2, 5, a multiple of either, or a product of these multiples will have a finite amount of decimals?
So any integer divided by any multiple of 5 will have a finite amount of decimals, etc.?
* And another basic question: 0 is neither positive nor negative right?
* I also don't completely understand what to do when we don't know whether the fraction is reduced to its lowest form. Can we still apply the same rule?
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nickk wrote: Bunuel please excuse the stupid question but I'm quite weak in these types of questions.
1.Does the rule basically say that any integer divided by either 2, 5, a multiple of either, or a product of these multiples will have a finite amount of decimals?
2. So any integer divided by any multiple of 5 will have a finite amount of decimals, etc.?
3. And another basic question: 0 is neither positive nor negative right?
4. I also don't completely understand what to do when we don't know whether the fraction is reduced to its lowest form. Can we still apply the same rule?
1. Not multiples but when denominator has only 2 and/or 5 in any integer power; 2. No, multiples of 5 are 5, 10, 15, 20, 25, 30, ... 1/30 won't be terminating as there is 3 in denominator. Maybe you meant 5 in any power? Then yes; 3. Yes, (though it's even); 4. If fraction has only 2 or/and 5 in denominator then it does not matter whether it's reduced. If there is some other integer in denominator we need reducing to see whether it can be cancelled.
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Thanks! that explains everything
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How to know these properties before, some book/site has these properties covered thoroughly.
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arnoorichenna wrote: How to know these properties before, some book/site has these properties covered thoroughly. gmat-math-book-87417.htmlMGMAT Strategy Guides 4th Edition OG12, OG Quantitative Review 2 Nothing else is required beyond these for GMAT related quantitative concepts.
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It is a repeat soln is explained in 700-question-94641.html
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Re: Does the decimal equivalent of P/Q, where P and Q are [#permalink]
26 Jan 2012, 03:15
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Re: Does the decimal equivalent of P/Q, where P and Q are
[#permalink]
26 Jan 2012, 03:15
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