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Does the line pass through Ist quadrant? 1) The intercept [#permalink]
 27 Apr 2006, 23:45
Does the line pass through Ist quadrant?
1) The intercept with x axis is -1.
2) The slope is greater than 1.
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getzgetzu wrote: Does the line pass through Ist quadrant?
1) The intercept with x axis is -1.
2) The slope is greater than 1.
I think must be B, if slope is greater than one it should pass by the first quadrant sometime no matter what
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getzgetzu wrote: Does the line pass through Ist quadrant?
1) The intercept with x axis is -1.
2) The slope is greater than 1.
Agree with B
(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1
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TeHCM wrote: Agree with B
(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1
TeHCM,
Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too
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giddi77 wrote: TeHCM wrote: Agree with B
(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1 TeHCM, Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too I'm still a bit rusty after all the rest. LOL. Could you elaborate?
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Agreed with B.
For (1) if the line is || to the Y axis (x=-1) then it does not, but for some it does!
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TeHCM wrote: giddi77 wrote: TeHCM wrote: Agree with B
(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1 TeHCM, Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too I'm still a bit rusty after all the rest. LOL. Could you elaborate? Now the line x = -1 (line that parallel to y-axis and passes through (-1,0)), satisfies both condition it's slope is infinity, which is defenitely > 1. Also it has x-intercept of -1. But it doesn't pass through 1st Quadrant.
Hence it should be E.
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giddi77 wrote: TeHCM wrote: giddi77 wrote: TeHCM wrote: Agree with B
(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1 TeHCM, Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too I'm still a bit rusty after all the rest. LOL. Could you elaborate? Now the line x = -1 (line that parallel to y-axis and passes through (-1,0)), satisfies both condition it's slope is infinity, which is defenitely > 1. Also it has x-intercept of -1. But it doesn't pass through 1st Quadrant. Hence it should be E. If line x = -1, shouldn't the slope = 0?
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TeHCM wrote: If line x = -1, shouldn't the slope = 0?
OK take 2 points (-1,0) & (-1,10) on the line x = -1
Now slope = (y2-y1)/(x2-x1) = 10-0/(-1-(-1)) = 10/0 = infinity!
A line parallel to x-axis has 0 slope.
A line parallel to y-axis has infinite slope
Googled and found this link. It has a java applet for visualization of lines & slopes
http://www.uncwil.edu/courses/mat111hb/functions/lines/lines.html
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giddi77 wrote: A line parallel to x-axis has 0 slope.
A line parallel to y-axis has infinite slope
I vaguely recall this in high school 
I will look into this, thanks!
p.s. you should go to sleep now!
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[quote="getzgetzu"]Does the line pass through Ist quadrant?
1) The intercept with x axis is -1.
2) The slope is greater than 1.[/quote]
E I think too. OA please
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somehow I tend to consider positive, negative, zero and inf four different slopes... and particularly I consider slope of inf is not defined!
in this case I would say B is sufficient, because, any positive slope line is bound to pass through quadrant (I and III) and negative slope will pass through quadrant(II, and IV)
more over any line with positive or negative slope passes through three quadrant!
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Ok to clarify my previous stand about slope let me quote bible (OG-11, page 138)
" For vertical line, slope is not defined......"
And if you remember numbers properties 0 is neither positive nor negative it’s just "even evil"
I hope this helps…
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chiragr wrote: Ok to clarify my previous stand about slope let me quote bible (OG-11, page 138)
" For vertical line, slope is not defined......"
And if you remember numbers properties 0 is neither positive nor negative it’s just "even evil"
I hope this helps…
Hmm.. If OG mentions "slope is not defined" for a vertical line, I would have to take that. In that case B is sufficient.
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getzgetzu, what is the OA?
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Interesting exchange of mails. Will go with B post chiragr's clarification.
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Okay.. I agree with a line x=c has a slope of infinity, which is greater than 1!
Hence, I change my case and vote for E...
Whats the OA?
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Agree with E. What is OA?
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