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Does the line pass through Ist quadrant? 1) The intercept

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Does the line pass through Ist quadrant? 1) The intercept [#permalink] New post 27 Apr 2006, 22:45
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Does the line pass through Ist quadrant?

1) The intercept with x axis is -1.
2) The slope is greater than 1.
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Re: Ist quadrant [#permalink] New post 27 Apr 2006, 23:41
getzgetzu wrote:
Does the line pass through Ist quadrant?

1) The intercept with x axis is -1.
2) The slope is greater than 1.



I think must be B, if slope is greater than one it should pass by the first quadrant sometime no matter what
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Re: Ist quadrant [#permalink] New post 28 Apr 2006, 00:29
getzgetzu wrote:
Does the line pass through Ist quadrant?

1) The intercept with x axis is -1.
2) The slope is greater than 1.


Agree with B

(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1
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Re: Ist quadrant [#permalink] New post 28 Apr 2006, 00:48
TeHCM wrote:
Agree with B

(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1

TeHCM,
Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too
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Re: Ist quadrant [#permalink] New post 28 Apr 2006, 00:51
giddi77 wrote:
TeHCM wrote:
Agree with B

(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1

TeHCM,
Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too


I'm still a bit rusty after all the rest. LOL. Could you elaborate?
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 [#permalink] New post 28 Apr 2006, 00:52
Agreed with B.


For (1) if the line is || to the Y axis (x=-1) then it does not, but for some it does!
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Re: Ist quadrant [#permalink] New post 28 Apr 2006, 00:56
TeHCM wrote:
giddi77 wrote:
TeHCM wrote:
Agree with B

(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1

TeHCM,
Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too


I'm still a bit rusty after all the rest. LOL. Could you elaborate?


Now the line x = -1 (line that parallel to y-axis and passes through (-1,0)), satisfies both condition it's slope is infinity, which is defenitely > 1. Also it has x-intercept of -1. But it doesn't pass through 1st Quadrant.
Hence it should be E.
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Re: Ist quadrant [#permalink] New post 28 Apr 2006, 01:03
giddi77 wrote:
TeHCM wrote:
giddi77 wrote:
TeHCM wrote:
Agree with B

(1) the line could be a straight line with an equation of x = -1
(2) Yes, always goes through Quad 1

TeHCM,
Your argument for #1 can be applied to #2 too. In which case the slope of line is infinity (> 1) and intercept is -1 too


I'm still a bit rusty after all the rest. LOL. Could you elaborate?


Now the line x = -1 (line that parallel to y-axis and passes through (-1,0)), satisfies both condition it's slope is infinity, which is defenitely > 1. Also it has x-intercept of -1. But it doesn't pass through 1st Quadrant.
Hence it should be E.


If line x = -1, shouldn't the slope = 0?
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Re: Ist quadrant [#permalink] New post 28 Apr 2006, 01:15
TeHCM wrote:
If line x = -1, shouldn't the slope = 0?


OK take 2 points (-1,0) & (-1,10) on the line x = -1
Now slope = (y2-y1)/(x2-x1) = 10-0/(-1-(-1)) = 10/0 = infinity!

A line parallel to x-axis has 0 slope.
A line parallel to y-axis has infinite slope

Googled and found this link. It has a java applet for visualization of lines & slopes
http://www.uncwil.edu/courses/mat111hb/functions/lines/lines.html
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Re: Ist quadrant [#permalink] New post 28 Apr 2006, 01:21
giddi77 wrote:
A line parallel to x-axis has 0 slope.
A line parallel to y-axis has infinite slope


I vaguely recall this in high school :roll: :roll:

I will look into this, thanks!

p.s. you should go to sleep now!
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Re: Ist quadrant [#permalink] New post 29 Apr 2006, 10:38
[quote="getzgetzu"]Does the line pass through Ist quadrant?

1) The intercept with x axis is -1.
2) The slope is greater than 1.[/quote]

E I think too. OA please
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 [#permalink] New post 29 Apr 2006, 14:23
somehow I tend to consider positive, negative, zero and inf four different slopes... and particularly I consider slope of inf is not defined!

in this case I would say B is sufficient, because, any positive slope line is bound to pass through quadrant (I and III) and negative slope will pass through quadrant(II, and IV)

more over any line with positive or negative slope passes through three quadrant!
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 [#permalink] New post 29 Apr 2006, 14:27
Ok to clarify my previous stand about slope let me quote bible (OG-11, page 138)

" For vertical line, slope is not defined......"

And if you remember numbers properties 0 is neither positive nor negative it’s just "even evil"

I hope this helps…
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 [#permalink] New post 29 Apr 2006, 14:45
chiragr wrote:
Ok to clarify my previous stand about slope let me quote bible (OG-11, page 138)

" For vertical line, slope is not defined......"

And if you remember numbers properties 0 is neither positive nor negative it’s just "even evil"

I hope this helps…


Hmm.. If OG mentions "slope is not defined" for a vertical line, I would have to take that. In that case B is sufficient.
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 [#permalink] New post 29 Apr 2006, 14:48
getzgetzu, what is the OA?
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 [#permalink] New post 30 Apr 2006, 06:35
Interesting exchange of mails. Will go with B post chiragr's clarification.
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 [#permalink] New post 03 May 2006, 03:52
Okay.. I agree with a line x=c has a slope of infinity, which is greater than 1!


Hence, I change my case and vote for E...

Whats the OA?
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 [#permalink] New post 03 May 2006, 06:27
Agree with E. What is OA?
  [#permalink] 03 May 2006, 06:27
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Does the line pass through Ist quadrant? 1) The intercept

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