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Going with B - stmt 2 alone is sufficient but 1 is not.

since -x|x| >0 ==> x < 0.

This means x - 3 < 0 and therefore we know that x - 3 is a negative number that is being squared. when you take the sqr root of the square of a negative number we should consider the negative root as the result.

Maybe I'm really far off on this one, but...
the square root of (x-3)^2...isn't that just (x-3)? So isn't the question asking, is x-3 = 3-x? And if you solve the equation, then the stem is just, is x = 3? If that's the case, then only A is correct...
What is OA? _________________

I think I'm mixed up with simplifying. Can somebody explain why sqrt((x-3)^2)=3-x isn't the same as (x-3)^2=(3-x)^2 ?

(x-3)^2=(3-x)^2 are equal. But the if squares of two numbers are equal doesn't mean that the numbers too are equal. They could be opposite in sign and still their squares would be the same.

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