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DS 3 gmat prep

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Manager
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DS 3 gmat prep [#permalink] New post 07 Nov 2007, 05:09
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
please explain this ..i dont have the OA.
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Manager
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 [#permalink] New post 07 Nov 2007, 07:44
I think the answer is C.

Statement 1 by itself gives us the following possibilities:

a=2,n=6

OR

a=4,n=3

OR

a=8,n=2

Statement 2 by itself doesnt give us the value of 'a' either.


Taking both statements together, we get the value of a=2


Is there something I am missing here?
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 [#permalink] New post 08 Nov 2007, 16:24
Could it be B?

We know 1*2*3*4*5*6*7*8 is a multiple of a^n and with n=6, the only option is 2^6
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 [#permalink] New post 08 Nov 2007, 20:44
cstefanita wrote:
Could it be B?

We know 1*2*3*4*5*6*7*8 is a multiple of a^n and with n=6, the only option is 2^6


You are spot on. I still cant figure out how statement 1 is sufficient by itself though.
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 [#permalink] New post 08 Nov 2007, 21:16
cstefanita wrote:
Could it be B?

We know 1*2*3*4*5*6*7*8 is a multiple of a^n and with n=6, the only option is 2^6



I agree that a^n, w/ n=6 that a can only be 2.

However, I fail to see anywhere in the original stem relating a to n.

All S2 says is n=6. The original stem says that a & n are + integers. Nothing more about a & n. It does say that a is divisble by 8! or 8! is a multiple of a.

I cannot see how B is correct. A as well, I don't see how it can't be correct as pointed at by JBS.


So i would go w/ C.
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 [#permalink] New post 08 Nov 2007, 21:25
jbs wrote:
I think the answer is C.

Statement 1 by itself gives us the following possibilities:

a=2,n=6

OR

a=4,n=3

OR

a=8,n=2

Statement 2 by itself doesnt give us the value of 'a' either.

Taking both statements together, we get the value of a=2

Is there something I am missing here?


The mind plays games. Thats the logic i had used to answer the post in the first place. Over a period of time, i actually forgot that and figured i might have made a mistake.....
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 [#permalink] New post 08 Nov 2007, 22:40
I get B.

Stat 1: a could be 4 & n could be 3 or a could be 2 & n could be 6. Insuff.

Stat 2: n = 6
Given: a^n is a factor of 8!
If n = 6 then the only value that 'a' can assume, in order to be a factor of 8! is 2. Suff.
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 [#permalink] New post 08 Nov 2007, 22:47
GK_Gmat wrote:
I get B.

Stat 1: a could be 4 & n could be 3 or a could be 2 & n could be 6. Insuff.

Stat 2: n = 6
Given: a^n is a factor of 8!
If n = 6 then the only value that 'a' can assume, in order to be a factor of 8! is 2. Suff.



Ok I agree its B.

My laptop screen is tiny so I couldnt really see the n in a^n in the original statement.
  [#permalink] 08 Nov 2007, 22:47
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