Find all School-related info fast with the new School-Specific MBA Forum

It is currently 30 Aug 2014, 14:51

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

DS 7

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
SVP
SVP
User avatar
Joined: 16 Oct 2003
Posts: 1816
Followers: 4

Kudos [?]: 35 [0], given: 0

GMAT Tests User
DS 7 [#permalink] New post 26 May 2004, 19:21
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Explainations please...
Attachments

d2.JPG
d2.JPG [ 11.67 KiB | Viewed 746 times ]

Senior Manager
Senior Manager
avatar
Joined: 02 Mar 2004
Posts: 330
Location: There
Followers: 1

Kudos [?]: 0 [0], given: 0

GMAT Tests User
 [#permalink] New post 26 May 2004, 20:57
xyz = 1 (2)
or x = y = 1 (2)

x(y^2+z^3) = 0 (2), or even number

B is the answer.
Senior Manager
Senior Manager
avatar
Joined: 23 Sep 2003
Posts: 295
Location: US
Followers: 1

Kudos [?]: 0 [0], given: 0

GMAT Tests User
 [#permalink] New post 27 May 2004, 04:34
B is sufficient.

If xyz is odd, then x, y and z are odd and x(y^2 + z^3) is even.

Statement 1 is insufficent; we don't know anything about y and z.
Intern
Intern
avatar
Joined: 04 May 2004
Posts: 6
Location: Midwest
Followers: 0

Kudos [?]: 0 [0], given: 0

answer [#permalink] New post 27 May 2004, 08:16
Ndidi,

Coud you please elaborate your sentence,
"If xyz is odd, then x, y and z are odd and x(y^2 + z^3) is even. "


Thanks.
Senior Manager
Senior Manager
avatar
Joined: 23 Sep 2003
Posts: 295
Location: US
Followers: 1

Kudos [?]: 0 [0], given: 0

GMAT Tests User
 [#permalink] New post 27 May 2004, 09:48
Hi Abacus,

If xyz is odd, then x, y and z are odd and x(y^2 + z^3) is even.


If xyz is odd, it means that x is odd, y is odd and z is odd. If any one of the three is even, then xyz would be even. Remember that 2 is a factor of every even number so x, y or z cannot be even.

If x, y and z are odd, then:

odd(odd^2 + odd^3) = even

odd^2 + odd^3 is even since the sum of 2 odd numbers is even.

odd * even is also even.
Intern
Intern
avatar
Joined: 04 May 2004
Posts: 6
Location: Midwest
Followers: 0

Kudos [?]: 0 [0], given: 0

Thanks [#permalink] New post 27 May 2004, 11:06
Hi ndidi,

Thank you for your explanation.
Thanks   [#permalink] 27 May 2004, 11:06
    Similar topics Author Replies Last post
Similar
Topics:
Is x > y ? (1) ax > ay (2) a^2x > a^2y milind1979 8 31 Mar 2009, 20:33
What is the volume of a certain rectangular solid? (1) Two milind1979 3 31 Mar 2009, 20:32
DS: t divided by 7 judokan 23 05 Sep 2008, 02:57
7 tricky PS and DS!!! eribold 3 18 Feb 2007, 13:44
DS - Geometry ETS Question #7 ucramitpatel 1 17 Nov 2006, 09:35
Display posts from previous: Sort by

DS 7

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.