DS Coordinate geometry

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DS Coordinate geometry [#permalink]

13 Jul 2011, 16:32

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In the rectangular coordinate system, are the points (v, w) and (x, y) equidistant from the origin?

1) v/w = x/y
2) sqrt(v^2) + sqrt(w^2)= sqrt(x^2) +sqrt(y^2)

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Re: DS Coordinate geometry [#permalink]

14 Jul 2011, 07:46

sm021984 wrote:

In the rectangular coordinate system, are the points (v, w) and (x, y) equidistant from the origin?

1) v/w = x/y
2) sqrt(v^2) + sqrt(w^2)= sqrt(x^2) +sqrt(y^2)

We know that the distance formula for a point from origin is {sqroot(a^2 + b^2)} --- Eq 1
where a,b are the co-ordinates.

So,
distance for point (v,w) D1= sqroot(v^2 + w^2)
distance for point (x,y) D2= sqroot(x^2 + y^2)

we have to find if D1 = D2

From statement 1: v, w can be any value Say 3,6 such that v/w=1/2
and x/y can be any value such that x/y = 1,2 . Therefore say x,y be 4,8

clearly this does not satisfies eq1 Hence not sufficient.

From statement 2 also it is clearly different from eq1. Not sufficient.

Statement 1,2 are also not sufficient together.

Hence E.

Please let me know if i am correct and the OA too

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Re: DS Coordinate geometry [#permalink]

14 Jul 2011, 08:16

sm021984 wrote:

In the rectangular coordinate system, are the points (v, w) and (x, y) equidistant from the origin?

1) v/w = x/y
2) sqrt(v^2) + sqrt(w^2)= sqrt(x^2) +sqrt(y^2)

St 1:V/W = X/Y......... clearly insufficient

St2: |v| + |w| = |X| + |y| ... Absolute value can give multiple values

1&2
we know v/w = x/y and |v| + |w| = |X| + |y|
sqrt(v^2) + sqrt(w^2)= sqrt(x^2) +sqrt(y^2)
sqrt(v^2) + sqrt(w^2)= sqrt(v^2) + sqrt(w^2)

hence C

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Re: DS Coordinate geometry [#permalink]

14 Jul 2011, 09:42

sudhir18n wrote:

sm021984 wrote:

In the rectangular coordinate system, are the points (v, w) and (x, y) equidistant from the origin?

1) v/w = x/y
2) sqrt(v^2) + sqrt(w^2)= sqrt(x^2) +sqrt(y^2)

Even i got the answer as E. What is the OA?

Sudhir18n,
I didn't understand the relation sqrt(v^2) + sqrt(w^2)= sqrt(x^2) +sqrt(y^2) implies
sqrt(v^2) + sqrt(w^2)= sqrt(v^2) + sqrt(w^2).
Could you please elaborate?
_________________

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Varun

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Re: DS Coordinate geometry [#permalink] 14 Jul 2011, 09:42

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