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if \(x^2=y+5\) and \(y=z-2\) and z=2x , is \(x^3+y^2+z\) divisible by 7?

1) x>0 2) y=4

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient If we substitute z and y with x in the three equations we have _________________

Your attitude determines your altitude Smiling wins more friends than frowning

D is the answer. St.1 By substitutions one can get the equation, x^2 - 2x-3 =0 Solving for x, x= +3 or -1; If x=3, then y=4 and z=6 Putting these values in, we get the result of 49 which is divisible by 7. However, if x= -1, we get 13 as the result and it is not divisible by 7. Therefore, St.1 is required and sufficient.

St. 2 By putting the values in, we get 49 that is divisible by 7. So, sufficient.

if \(x^2=y+5\) and \(y=z-2\) and z=2x , is \(x^3+y^2+z\) divisible by 7?

1) x>0 2) y=4

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient If we substitute z and y with x in the three equations we have

What is the OA dude ? B is very tempting.. but when i try stem 1 with x=1,2,3,4, and 5.. only x=3 seems to satisfy all the 3 equations in the question. So D is looks realistic. what is the source and OE ?

if \(x^2=y+5\) and \(y=z-2\) and z=2x , is \(x^3+y^2+z\) divisible by 7?

1) x>0 2) y=4

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient If we substitute z and y with x in the three equations we have

(1)here solving eqns we get x=-1,3 => 3 gives div by 7 but when x=-1 the expr is noit div => INSUFFI (2)gives x=3 and hence when substituted the expr is div by 7 SUFFI

if \(x^2=y+5\) and \(y=z-2\) and z=2x , is \(x^3+y^2+z\) divisible by 7?

1) x>0 2) y=4

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient If we substitute z and y with x in the three equations we have

(1)here solving eqns we get x=-1,3 => 3 gives div by 7 but when x=-1 the expr is noit div => INSUFFI (2)gives x=3 and hence when substituted the expr is div by 7 SUFFI

IMO B

i made silly mistake overlooked x>0 oh god!!! _________________