Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: DS_divisibility [#permalink]
10 Oct 2007, 00:48

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer? c = 2 a = b + c

Hi,

the equation can be rewritten as (ac/b).

Stat. 1 is not sufficient let's take a=1, b=3 and c=2 the result is not an integer. And if we take b=4 the result is an integer.

Stat. 2 gives us [(b+c)c]/b = b + (c²/b).
if c=2 and b=3, the result is not an integer.
if c=2 and b=4 the result is an integer => thus stat. 2 not sufficient

Combining 1 & 2 we have both cases (integer and non integer)

Re: DS_divisibility [#permalink]
10 Oct 2007, 00:52

ronneyc wrote:

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer? c = 2 a = b + c

Hi,

the equation can be rewritten as (ac/b).

Stat. 1 is not sufficient let's take a=1, b=3 and c=2 the result is not an integer. And if we take b=4 the result is an integer.

Stat. 2 gives us [(b+c)c]/b = b + (c²/b). if c=2 and b=3, the result is not an integer. if c=2 and b=4 the result is an integer => thus stat. 2 not sufficient

Combining 1 & 2 we have both cases (integer and non integer)

Re: DS_divisibility m05 #36 [#permalink]
26 Jun 2014, 22:18

2

This post received KUDOS

A: Insuff. Given a, b are distinct integers, a/b must be an even integer. a=4, b=1 - true. a=9, b=3 - false. Both, true & false possible. Hence, inconclusive. B: On simplifying, given b, c are distinct integers, (1/b + 1/c) must be an integer. For any b,c where b <> c, this is false. Hence, conclusive.

Thus, B.

gmatclubot

Re: DS_divisibility m05 #36
[#permalink]
26 Jun 2014, 22:18