DS_divisibility m05 #36

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If a, b, and c are positive distinct integers, is (a/b)/c an [#permalink]

10 Oct 2007, 00:40

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If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

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Re: DS_divisibility [#permalink]

10 Oct 2007, 01:48

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

Hi,

the equation can be rewritten as (ac/b).

Stat. 1 is not sufficient let's take a=1, b=3 and c=2 the result is not an integer. And if we take b=4 the result is an integer.

Stat. 2 gives us [(b+c)c]/b = b + (c²/b).
if c=2 and b=3, the result is not an integer.
if c=2 and b=4 the result is an integer => thus stat. 2 not sufficient

Combining 1 & 2 we have both cases (integer and non integer)

My ans. is E

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Re: DS_divisibility [#permalink]

10 Oct 2007, 01:52

ronneyc wrote:

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

I missed (a) in stat 1 ... take b=4 and a=6

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Re: DS_divisibility [#permalink]

10 Oct 2007, 04:05

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B
1. doesnt give info about others
2. suff.

(a/b)/c=a/bc

(b+c)/bc

1/b+1/c

since b and c are disticnt positive integers and b is not equal to c
the expression cannot be an integer

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Re: DS_divisibility [#permalink]

10 Oct 2007, 04:32

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

tricky.
tempting to say C but it is B i think.

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Re: DS_divisibility [#permalink]

10 Oct 2007, 05:59

Ravshonbek wrote:

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B
1. doesnt give info about others
2. suff.

(a/b)/c=a/bc

(b+c)/bc

1/b+1/c

since b and c are disticnt positive integers and b is not equal to c
the expression cannot be an integer

Welldone Rav. Got B 2!
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[#permalink]

10 Oct 2007, 08:40

Again late B

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Re: DS_divisibility [#permalink]

10 Oct 2007, 10:39

IrinaOK wrote:

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B.

Q: (a/b)/c = (a/bc)
S1: Insuff
S2: a = b+c ==> (b+c)/bc - is always a fraction for any set of distinct positive integers - Suff

Re: DS_divisibility [#permalink] 10 Oct 2007, 10:39

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DS_divisibility m05 #36

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DS_divisibility m05 #36

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