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# DS-Geometry(Parallelogram)

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Manager
Joined: 04 Sep 2007
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DS-Geometry(Parallelogram) [#permalink]  01 Jul 2008, 13:00
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Can someone help me with this (see attached word document)? Unfortunately, I do not have the OA for this one. I picked B as the answer as the two lengths (QR and PS) are equal. Thanks in advance for the help.
Attachments

DS-Parallelogram.doc [79.5 KiB]

Director
Joined: 01 Jan 2008
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Re: DS-Geometry(Parallelogram) [#permalink]  01 Jul 2008, 13:10
1) insufficient -> P can be anywhere on the line parallel to QS and the same distance from QS as R
2) insufficient -> P can be anywhere

1&2: insufficient P can be anywhere on the line parallel to QS and the same distance from QS as R
PRQS is only going to be a parallelogram if P and R are symmetrical with respect to QS.

Current Student
Joined: 28 Dec 2004
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Location: New York City
Schools: Wharton'11 HBS'12
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Re: DS-Geometry(Parallelogram) [#permalink]  01 Jul 2008, 17:32
my guess would be E as welll..

a parallelogram is one that has all opposite sides parallel..

in our case we only know about QR and RS..nothing about the other 2 sides..
Manager
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Re: DS-Geometry(Parallelogram) [#permalink]  01 Jul 2008, 20:26
Agreed. Thanks for helping out with your explanations.
Re: DS-Geometry(Parallelogram)   [#permalink] 01 Jul 2008, 20:26
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