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ds integers

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joemama142000
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ds integers [#permalink] New post   14 Jan 2006, 04:08
00:00
A
B
C
D
E

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(N/A)

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what is the value of (x-a)-(x-b)-(x-c)-(x-d)?

1)the average of a,b,c,d is x
2)a,b,c,d are consecutive integers



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Re: ds integers [#permalink] New post   14 Jan 2006, 05:14
Is it A??

Y = (x-a)-(x-b)-(x-c)-(x-d) = 4x - (a+b+c+d)

St1:

4x = a+b+c+d

So Y = 0 SUFF
St2:
We don't know anything about x. So INSUFF
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Re: ds integers [#permalink] New post   14 Jan 2006, 06:19
IMO it is E.
(x-a)-(x-b)-(x-c)-(x-d)=b+c+d-a-2x.

1 St. (a+b+c+d)/4=x => 4x-2a-2x=2x-2a => insuf. We donn`t know x and a.
2 St. We also have no information about x.
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Re: ds integers [#permalink] New post   14 Jan 2006, 09:15
C

The question asks what is (x-a) - (x-b) - (x-c) - (x-d)

which is: b + c + d - a - 2x?

1st statement gives a + b+ c +d = 4x
Second statement gives b = a+1, c = a+2, d = a+3

Now substitute it in 1st statement
a + a+1 + a+2 + a+3 = 4x
4a + 6 = 4x
2a + 3 = 2x

Now go back to question
b+c+d-a-2x
a+1+a+2+a+3-a-2x ==> 2a + 6 -2x
but you know 2x -2a = 3
so -3 + 6 = 3

Is this the OA?
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Re: ds integers [#permalink] New post   14 Jan 2006, 09:22
willget800 wrote:
C

The question asks what is (x-a) - (x-b) - (x-c) - (x-d)

which is: b + c + d - a - 2x?

1st statement gives a + b+ c +d = 4x
Second statement gives b = a+1, c = a+2, d = a+3

Now substitute it in 1st statement
a + a+1 + a+2 + a+3 = 4x
4a + 6 = 4x
2a + 3 = 2x

Now go back to question
b+c+d-a-2x
a+1+a+2+a+3-a-2x ==> 2a + 6 -2x
but you know 2x -2a = 3
so -3 + 6 = 3

Is this the OA?

Good Job!IMHO it is right approach
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Re: ds integers [#permalink] New post   14 Jan 2006, 14:40
ps_dahiya wrote:
Is it A??

Y = (x-a)-(x-b)-(x-c)-(x-d) = 4x - (a+b+c+d)

St1:

4x = a+b+c+d

So Y = 0 SUFF
St2:
We don't know anything about x. So INSUFF


This is what happens at 4 AM :beat
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Re: ds integers [#permalink] New post   14 Jan 2006, 20:39
willget800 wrote:
C

The question asks what is (x-a) - (x-b) - (x-c) - (x-d)

which is: b + c + d - a - 2x?

1st statement gives a + b+ c +d = 4x
Second statement gives b = a+1, c = a+2, d = a+3

Now substitute it in 1st statement
a + a+1 + a+2 + a+3 = 4x
4a + 6 = 4x
2a + 3 = 2x

Now go back to question
b+c+d-a-2x
a+1+a+2+a+3-a-2x ==> 2a + 6 -2x
but you know 2x -2a = 3
so -3 + 6 = 3

Is this the OA?


Very elegant solution. IT has to be C
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Re: ds integers [#permalink] New post   14 Jan 2006, 22:06
ps_dahiya wrote:
ps_dahiya wrote:
Is it A??

Y = (x-a)-(x-b)-(x-c)-(x-d) = 4x - (a+b+c+d)

St1:

4x = a+b+c+d

So Y = 0 SUFF
St2:
We don't know anything about x. So INSUFF


This is what happens at 4 AM :beat


Hmmmm....so you study till 4AM :)
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Re: ds integers [#permalink] New post   14 Jan 2006, 22:53
But guys,
Stmt 2 hjust says tht a,b,c,d are cons integers we dont know which one is the smallest

So it can be a,a+2,a+2,a+3 or if B is small then the series wud be
B,A,C,D means b,b+1,b+2,b+3

So i would go with E.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: ds integers [#permalink]
14 Jan 2006, 22:53
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