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# DS is X>Y ?

Author Message
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Intern
Joined: 16 Feb 2010
Posts: 28
Followers: 0

Kudos [?]: 4 [0], given: 0

DS is X>Y ? [#permalink]  01 May 2010, 06:25
00:00

Difficulty:

(N/A)

Question Stats:

100% (02:55) correct 0% (00:00) wrong based on 1 sessions
Is x >y ?
(1) x + y > 0
(2) x^2–y^2> 0

Senior Manager
Joined: 30 Aug 2009
Posts: 286
Location: India
Concentration: General Management
Followers: 3

Kudos [?]: 131 [0], given: 5

Re: DS is X>Y ? [#permalink]  01 May 2010, 08:02
poohv005 wrote:
Is x >y ?
(1) x + y > 0
(2) x^2–y^2> 0

stmnt1 - x= 2 y = 0 then x + y > 0 and x>y
x= 1 and y =2 then x + y > 0 and x<y hence insuff

stmnt2 - x= 2 and y = 0 then x^2–y^2> 0 and x>y
x= -5 and y = 4 then x^2–y^2> 0 but x<y hence insuff

taking both together we have x + y > 0 and x^2–y^2> 0
==> x^2–y^2> 0 = (x+y)(x-y) > 0
==> we have (x+y) is >0 so x-y>0 or x>y. hence C
Re: DS is X>Y ?   [#permalink] 01 May 2010, 08:02
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