Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

X is a mode of [3, 0, 1, -1, 0, 5, 1] X is neither positive nor negative

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient

(1) has 1,0 as mods INSUFFI (2) 0 is the only number neither +ve nor -ve SUFFFI IMO B _________________

Re: ds - mode (m05q32) [#permalink]
05 Aug 2010, 05:24

Quote:

tiruraju -

That would never be a question because both statements 1 and 2 MUST be true. In your case, that is not possible.

Agreed, this is not a 'legal' question. One of the basic principles of DS is that the two statements CANNOT contradict one another. In this case, both statements provide a unique answer (stmt one = 1 and stmt two = 0) which contradict.

With that said, if on the GMAT you find yourself where the statements contradict, you have done something wrong.

HTHs, Martin. _________________

I appreciate the kudos if you find this post helpful! +1

Re: ds - mode (m05q32) [#permalink]
08 Aug 2012, 06:08

san1987 wrote:

stmt 1: using the formula: mode = ( 3 * median ) - ( 2 * mean) u can calculate mode....

hence A is sufficient ...

stmt 2: using this also v can say mode = 0 as its neither positive nor negative...

so ans has to D...

but y its B ??? ani one plz explain

Not sure where you are getthing this calculation of mode from. But here is the definition of mode: The number which appears most often in a set of numbers. Therefore it could be either 0 or 1. A is INSUFFICIENT.

Re: ds - mode (m05q32) [#permalink]
29 Aug 2012, 06:34

Did not really find this one that hard to solve. Looking at A and then B, I did tend to think that C screamed at me but then B does give the value as 0. So B it is. _________________

My attempt to capture my B-School Journey in a Blog : tranquilnomadgmat.blogspot.com

The mode is the number that occurs the most frequently in a data set. For example the mode of {2, 3, 4, 4} is 4. A set can have more than one mode, for example set {2, 2, 3, 3, 5} has 2 modes 2 and 3. If every number in a set occurs an equal number of times, then the set has no mode. For example set {1, 2, 3} has no mode.

So, according to above {3, 0, 1, -1, 0, 5, 1} has two modes 0 and 1, which means that \(x\) can be either of these two values. Not sufficient.

(2) \(x\) is the median of {-4, 4, 2, -2} --> the median of a set with even number of terms is the average of two middle terms when arranged in ascending/descending order. So, the median of {-4, -2, 2, 4} is (-2+2)/2=0 --> \(x=0\). Sufficient.