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# ds - mode (m05q32)

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ds - mode (m05q32) [#permalink]  04 Sep 2008, 12:07
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What is the value of $$X$$ ?

1. $$X$$ is a mode of $$[3, 0, 1, -1, 0, 5, 1]$$
2. $$X$$ is neither positive nor negative

[Reveal] Spoiler: OA
B

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Re: ds -mode [#permalink]  04 Sep 2008, 19:47
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OA is B.

thanks for the replies.
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Re: ds - mode (m05q32) [#permalink]  27 May 2010, 02:50
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what does mode mean ?
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Re: ds -mode [#permalink]  05 Sep 2008, 21:08
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x2suresh wrote:
What is the value of X?

X is a mode of [3, 0, 1, -1, 0, 5, 1]
X is neither positive nor negative

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient

(1) has 1,0 as mods INSUFFI
(2) 0 is the only number neither +ve nor -ve SUFFFI
IMO B
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Re: ds - mode (m05q32) [#permalink]  28 May 2010, 07:51
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leilak wrote:
what does mode mean ?

http://en.wikipedia.org/wiki/Mode_(statistics)

"In statistics, the mode is the value that occurs the most frequently in a data set or a probability distribution."

So from (1), the mode is either 0 or 1 since both have two occurrences.
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Re: ds -mode [#permalink]  04 Sep 2008, 12:54
b.

st1 mode can be 0 or 1
st2 0 is the only number neither pos nor neg.
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Re: ds -mode [#permalink]  04 Sep 2008, 14:21
x2suresh wrote:
What is the value of X?

X is a mode of [3, 0, 1, -1, 0, 5, 1]
X is neither positive nor negative

X is a mode of [3, 0, 1, -1, 0, 5, 1]

mode is 0 and 1 . Lets NOT avg them like we do for finding the median of set

aka bi modal. So X = 0,1

there can be sets with more than 2 modes and no mode at all.

Insuff

Only one value such that its not +ve or -ve ie 0

Suff

Hence B
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Re: ds - mode (m05q32) [#permalink]  03 Aug 2010, 10:08
Hi Guys,

A small change done to the actual question ( removed the zeros from the option 1)

What is the value of ?

1. is a mode of [3, 1, -1, 5, 1]
2. is neither positive nor negative

In this case , will the answer be

D ( X would be 1 based in option 1 AND 0 based on the option 2)
or
E ( eventhough X value is determined in both the cases , the values are different)

Thanks,
Raju
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Re: ds - mode (m05q32) [#permalink]  03 Aug 2010, 15:07
tiruraju wrote:
Hi Guys,

A small change done to the actual question ( removed the zeros from the option 1)

What is the value of ?

1. is a mode of [3, 1, -1, 5, 1]
2. is neither positive nor negative

In this case , will the answer be

D ( X would be 1 based in option 1 AND 0 based on the option 2)
or
E ( eventhough X value is determined in both the cases , the values are different)

Thanks,
Raju

i think it would be E- cant find one unique answer due to 2 mode values....(x>0 for example would make it easier!)

thanks
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Re: ds - mode (m05q32) [#permalink]  03 Aug 2010, 19:54
tiruraju -

That would never be a question because both statements 1 and 2 MUST be true. In your case, that is not possible.
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Re: ds - mode (m05q32) [#permalink]  05 Aug 2010, 05:24
Quote:
tiruraju -

That would never be a question because both statements 1 and 2 MUST be true. In your case, that is not possible.

Agreed, this is not a 'legal' question. One of the basic principles of DS is that the two statements CANNOT contradict one another. In this case, both statements provide a unique answer (stmt one = 1 and stmt two = 0) which contradict.

With that said, if on the GMAT you find yourself where the statements contradict, you have done something wrong.

HTHs, Martin.
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Re: ds - mode (m05q32) [#permalink]  04 Aug 2011, 08:34
This one was so tricky!! I chose C first, but B is the right answer.
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Re: ds - mode (m05q32) [#permalink]  04 Aug 2011, 09:59
easy one...0 is the answer & 2nd stmt is sufficient
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Re: ds - mode (m05q32) [#permalink]  08 Aug 2011, 03:06
It's a nice one.
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Re: ds - mode (m05q32) [#permalink]  09 Aug 2011, 11:35
stmt 1:
using the formula:
mode = ( 3 * median ) - ( 2 * mean)
u can calculate mode....

hence A is sufficient ...

stmt 2:
using this also v can say mode = 0 as its neither positive nor negative...

so ans has to D...

but y its B ???
ani one plz explain
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Re: ds - mode (m05q32) [#permalink]  08 Aug 2012, 05:59
(1) Bi-modal -0,1-not sufficient
(2)zero-sufficient
(B) wins
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Re: ds - mode (m05q32) [#permalink]  08 Aug 2012, 06:06
Easy!

1) INSUFFICIENT- could be either 0 or 1.
2) SUFFICIENT- only number that is neither positive nor negative is 0.

B!
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Re: ds - mode (m05q32) [#permalink]  08 Aug 2012, 06:08
san1987 wrote:
stmt 1:
using the formula:
mode = ( 3 * median ) - ( 2 * mean)
u can calculate mode....

hence A is sufficient ...

stmt 2:
using this also v can say mode = 0 as its neither positive nor negative...

so ans has to D...

but y its B ???
ani one plz explain

Not sure where you are getthing this calculation of mode from. But here is the definition of mode: The number which appears most often in a set of numbers. Therefore it could be either 0 or 1. A is INSUFFICIENT.
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Re: ds - mode (m05q32) [#permalink]  29 Aug 2012, 06:34
Did not really find this one that hard to solve. Looking at A and then B, I did tend to think that C screamed at me but then B does give the value as 0. So B it is.
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Re: ds - mode (m05q32) [#permalink]  29 Aug 2012, 06:50
Expert's post
x2suresh wrote:
What is the value of $$X$$ ?

1. $$X$$ is a mode of $$[3, 0, 1, -1, 0, 5, 1]$$
2. $$X$$ is neither positive nor negative

[Reveal] Spoiler: OA
B

Source: GMAT Club Tests - hardest GMAT questions

REVISED VERSION OF THIS QUESTION IS BELOW:

What is the value of $$x$$ ?

(1) $$x$$ is the mode of {3, 0, 1, -1, 0, 5, 1}.

The mode is the number that occurs the most frequently in a data set. For example the mode of {2, 3, 4, 4} is 4. A set can have more than one mode, for example set {2, 2, 3, 3, 5} has 2 modes 2 and 3. If every number in a set occurs an equal number of times, then the set has no mode. For example set {1, 2, 3} has no mode.

So, according to above {3, 0, 1, -1, 0, 5, 1} has two modes 0 and 1, which means that $$x$$ can be either of these two values. Not sufficient.

(2) $$x$$ is the median of {-4, 4, 2, -2} --> the median of a set with even number of terms is the average of two middle terms when arranged in ascending/descending order. So, the median of {-4, -2, 2, 4} is (-2+2)/2=0 --> $$x=0$$. Sufficient.

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Re: ds - mode (m05q32)   [#permalink] 29 Aug 2012, 06:50

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