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# DS Newspaper

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Senior Manager
Joined: 22 May 2003
Posts: 334
Location: Uruguay
Followers: 1

Kudos [?]: 35 [0], given: 0

DS Newspaper [#permalink]  08 Jan 2004, 08:54
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
DS Newspaper
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DS - Newspaper.jpg [ 19.46 KiB | Viewed 608 times ]

Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 10 [0], given: 0

dj-- that's what I get at first blush too, but I think it's wrong.

Just to make the math easier, say that 28 (rather than 27) percent of the population don't buy either paper.

That means that 72 percent buy X, Y, or both.

If they are in a 7:1 ratio, it could be that 63% buy X, and 9% buy y.
or, it could mean that 62% buy x exclusively, and 2% buy y exclusively, and that 8% buy both..

(2) solves this problem. I think we need them both.
Director
Joined: 13 Nov 2003
Posts: 971
Location: Florida
Followers: 1

Kudos [?]: 31 [0], given: 0

damn

see what I did...
% Y = Y/(X+Y) = Y/8Y
means 1/8 of X and Y

A tells us that 80% is X and Y
Senior Manager
Joined: 22 May 2003
Posts: 334
Location: Uruguay
Followers: 1

Kudos [?]: 35 [0], given: 0

stoolfi wrote:
dj-- that's what I get at first blush too, but I think it's wrong.

Just to make the math easier, say that 28 (rather than 27) percent of the population don't buy either paper.

That means that 72 percent buy X, Y, or both.

If they are in a 7:1 ratio, it could be that 63% buy X, and 9% buy y.
or, it could mean that 62% buy x exclusively, and 2% buy y exclusively, and that 8% buy both..

(2) solves this problem. I think we need them both.

We are looking for the percent of the population that purchase newspaper Y, and not
the percent of the population that purchase exclusively newspaper Y.

Therefore, the two situations you proposed against A will draw the same result. Here's an example:

Supose there are 100 people.

Case 1: 62 purchase X exclusively and 9 purchase Y exclusively

Then the answer would be obviously 9%

Total number of people buying paper Y = 7+2 = 9

Do I make any sense?

This is a Kaplan question btw and the answer provided is C, although I still believe is A.

Martin
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 10 [0], given: 0

Quote:
Case 1: 62 purchase X exclusively and 9 purchase Y exclusively

Then the answer would be obviously 9%

Total number of people buying paper Y = 7+2 = 9

Except in the first example, the ratio is 62:9, and in the second, the ratio is 69:9
Senior Manager
Joined: 22 May 2003
Posts: 334
Location: Uruguay
Followers: 1

Kudos [?]: 35 [0], given: 0

stoolfi wrote:
Quote:
Case 1: 62 purchase X exclusively and 9 purchase Y exclusively

Then the answer would be obviously 9%

Total number of people buying paper Y = 7+2 = 9

Except in the first example, the ratio is 62:9, and in the second, the ratio is 69:9

Good point, my mistake.
SVP
Joined: 30 Oct 2003
Posts: 1797
Location: NewJersey USA
Followers: 5

Kudos [?]: 41 [0], given: 0

Let me know if I am right in the following approach

100 = X + Y + Neither - Both

We know that X/Y = 7/1 or X = 7Y
Statement 1 provides "Neither"
Statement 2 provides "Both"

So 100 = 7Y + Y + 27 - 0.7Y
73 = 7.3Y hence Y = 10 So X = 70

So Both are required to to findout Y.
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