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ds og 10 TH 263

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ds og 10 TH 263 [#permalink] New post 05 Dec 2005, 11:33
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:) is m not equal to n?

ST 1 m+n<O

ST 2 mn<0


seems easy but i get quite stuck

plz post your approach

thanks
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 [#permalink] New post 05 Dec 2005, 12:37
I feel like the answer is B...

Statements:
1) m+n<0 - m and n can both be negative numbers and still satisfy the equation, or either m or n can be negative and the other positive and the equation will still be satisfied. Thus, InSuff.

2)The only way you could get mn <0 is if one of those numbers is a negative. If both are negative, then multiplied together, they'll be greater than zero.
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 [#permalink] New post 05 Dec 2005, 19:28
(1) m=-1 and n=-1; -2<0
m=-1 and n=-2; -3<0

Not sufficient

(2) if nm<0 then n and m can not have the same sign. They are different. Therefore ST2 is sufficient.

B
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Re: ds og 10 TH 263 [#permalink] New post 05 Dec 2005, 20:31
mand-y wrote:
:) is m not equal to n?

ST 1 m+n<O

ST 2 mn<0


seems easy but i get quite stuck

plz post your approach

thanks


Answer is B

Is m ≠ n?

(1) m + n < 0 ==> Many possibilities. Not sufficient.
(2) mn < 0 ==> m and n could not both be zero and m, and both have different signs otherwise mn > 0. Sufficient.

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Re: ds og 10 TH 263   [#permalink] 05 Dec 2005, 20:31
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