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ds og 10 # 11

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Manager
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ds og 10 # 11 [#permalink] New post 27 Nov 2005, 13:14
00:00
A
B
C
D
E

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(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
:) if m and n are consecutive integers

IS m Bigger than n ?

st 1 m-1 and n-1 are consecutives positives integers
st 2 m is an even integer

plz explain your approach

thanks
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Director
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Re: ds og 10 # 11 [#permalink] New post 27 Nov 2005, 15:52
mand-y wrote:
:) if m and n are consecutive integers

IS m Bigger than n ?

st 1 m-1 and n-1 are consecutives positives integers
st 2 m is an even integer

plz explain your approach

thanks

E

stm1 let say m = 4 , n =5 its statisfy the condition but m=5,n=4 also satisfy the condition ..hence Not Suff

stm2 Not Suff

taking together ...

let say m =4 (even Integer) and n =5 m <n
m = 6 and n = 5 m > n

not Suff

hence E
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 [#permalink] New post 27 Nov 2005, 17:59
mand-y wrote:
nope it is not E

okie, the question as it is, it is E. if it is not E, you might be missing an important piece of information. check the question again. :lol:
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CORRECTED [#permalink] New post 28 Nov 2005, 06:59
:oops: sorry I made a mistake in the sign

IS m Bigger than n ?

st 1 m-1 and n+1 are consecutives positives integers
st 2 m is an even integer
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OE [#permalink] New post 28 Nov 2005, 06:59
well E was my first answer.... Let 's me post the official explanation

I quote " :
note that for the two consecutive integers the larger must be 1 more than the smaller .that st1 alone is sufficient can probably be seen most easily by considering particular values of m and n .
for example if m =4 Then n=3 or 5 since m and n are consecutive
then m -1= 3 AND n +1 =4 or 6 since m-1 and n+ 1 are consecutive, m bigger than n .

more generally since m and n are consecutive either m= n+1
or n=m+1.

but if n=m+1. then n+1=m+2, which is 3 more than m-1 , contradicting the fact that m-1 and n+1 are consecutive integer .
THus m=n+1 OR m bigger than n
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 [#permalink] New post 23 Dec 2005, 23:49
I got A for this.

If m-1 and n-1 are consecutive,lets consider m-1 = 16 and n-1=17, then m=17 and n=18, this equation is suff for any other value as well.

St B is totally inuff, Hence A.
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 [#permalink] New post 24 Dec 2005, 22:03
If statements are

st 1 m-1 and n-1 are consecutives positives integers
st 2 m is an even integer


then E

If statements are

st 1 m-1 and n+1 are consecutives positives integers
st 2 m is an even integer


then A
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  [#permalink] 24 Dec 2005, 22:03
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