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Intern
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13 Aug 2009, 09:51
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GMAT club question

Is X > Y square ?
1. X > Y + 5
2. X square – Y square = 0
Statement (1) by itself is insufficient. Consider x, y = 5, -1 or 5, -3
Statement (2) by itself is insufficient. Consider x, y = 1/2, 1/2 or 2, 2
Statements (1) and (2) combined are sufficient. The absolute values of x and y are equal and x>y , implying that x is positive and y is negative. Therefore, X > Y2 is false.
----------------------

what if, x = 1/2 and y = -1/2 ? that makes x > y square true. Am I getting this wrong?

Manager
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13 Aug 2009, 10:37
1) X > Y + 5
let x = 1 and y = -6 then x < Y^2
let x=7 and y = 1 then x > y^2
So 1 alone is not sufficient

2) X^2 - Y^2 = 0
X = + Y
if x = -4 and y = 4 then X < Y^2
if x = 4 and y = -4 then X > Y^2
So 2 alone is not sufficient.

Combining 1 and 2
let x = 7 and Y = -7 then X > Y^2
let x = 1/4 and Y = -21/4 then X < Y^2
Intern
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13 Aug 2009, 11:04
Thanks for the confirmation.

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19 Aug 2009, 06:12
santoshsingh wrote:
GMAT club question

what if, x = 1/2 and y = -1/2 ? that makes x > y square true. Am I getting this wrong?

You're violating S1: $$\frac{1}{2} > -\frac{1}{2} +5$$ -- FALSE

Aleehsgonji wrote:
Combining 1 and 2
let x = 7 and Y = -7 then X > Y^2
let x = 1/4 and Y = -21/4 then X < Y^2

You must be violating S2. $$x= \pm y$$. If that is a typo and you really meant $$y=-\frac{1}{4}$$, then you're violating S1. I still think the answer must be C.

Am I right or am I missing something big here? Hope this helps.
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05 Sep 2009, 18:12
Expert's post
What is OA.

I see it C.

Combining (1) and (2) we have only positive x and negative y for which x^2=y^2. Q is x>y^2 answer NO

So (1) and (2) suff

Any Thoughts?
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