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# DS: Raffle Tickets - GMATPrep

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VP
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DS: Raffle Tickets - GMATPrep [#permalink]

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24 Nov 2006, 21:36
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< I couldn't find the question after searching, so I just post it here. If you have never tried the GMATPrep yet, it is not advised to read further. >

Did one of the 3 members of a certain team sell at least 2 raffle tickets yesterday?

1). The 3 members sold a total of 6 raffle tickets yesterday.
2). No 2 of the members sold the same number of tickets yesterday.

Senior Manager
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Re: DS: Raffle Tickets - GMATPrep [#permalink]

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24 Nov 2006, 21:46
Going for A

From 1)
Average = 6/3 = 2
Either each member sold 2 or if any one of them sold less than 2 then some other member sold greater than 2..

From 2) Not suff
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24 Nov 2006, 22:41
D for me

(1) SUFF - No matter what numbers you pick, one of the member will have sold at least 2

(2) SUFF - posssible numbers

3+2+1
5+1+0
0+0+6

same thing here. one of the members will have sold at least 2
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Impossible is nothing

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24 Nov 2006, 22:52
Got the point it should be D

From 2)
if 1st member = 0, 2nd member = 1 then the 3rd member has to be >= 2
VP
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24 Nov 2006, 23:25
Hermione wrote:
D for me

(1) SUFF - No matter what numbers you pick, one of the member will have sold at least 2

(2) SUFF - posssible numbers

3+2+1
5+1+0
0+0+6

same thing here. one of the members will have sold at least 2

Why do you say (2)'s total is 6 tickets?
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25 Nov 2006, 01:14
Sorry warren (buffet ), wrong explanation for (2). Anindyat's expanation is correct.

If first member sells 0, second member sells 1, then the 3rd member will have to sell 2 or more.
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VP
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25 Nov 2006, 02:02
I chose A too in the GMATPrep.

but OA is D, which puzzles me.

what does (2) alone mean? it only says 2nd member sell the same no of tickets. It does not say anything about any member selling more than 2 tickets, or the total tickets sold.

what do you think? I searched in the forum, but I am the first one to post this problem.
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25 Nov 2006, 06:01
2). No 2 of the members sold the same number of tickets yesterday.

statement 2 means that no member sold the same # of tickets.

so the 3 members could have sold 100, 8, 53 tickets each, all of which are greater 2. But we want to know if at least one of them sold 2 tickets so we use the minimum number of tickets that could have been sold if every member sold a different # of tickets.

this is why we use 0 tickets sold for member#1, since 0 the least amount that could have been sold

next smalles number is 1. next is 2.

so for sure, the 3rd person would've sold 2 tickets.

Hope my explanation helps
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VP
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25 Nov 2006, 08:40
OK. thanks a lot.
I thought No 2 is No. 2. WTH.
25 Nov 2006, 08:40
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