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# DS-Remainer

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Joined: 23 Aug 2006
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27 Oct 2006, 09:30
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Can anyone help?
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Senior Manager
Joined: 08 Jun 2006
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27 Oct 2006, 13:48
I am getting A

From 1
t throws remainder 6 when divided by 7, so t^2 will throw [6 * 6 â€“ maximum multiple of 7 less than 6 * 6] as remainder
= 36 â€“ 35 = 1

5t throws remainder = 5 * 6 - maximum multiple of 7 less than 5 * 6 = 30 â€“ 28 = 2

Total remainder for t^2 + 5t + 6
= 1 + 2 + 6 â€“ maximum multiple of 7 less than 1 + 2 + 6
= 9 â€“ 7 = 2

Sufficient - r = 2

From 2
I donâ€™t think we can derive the remainder for t from the remainder of t^2
Not sufficient
27 Oct 2006, 13:48
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