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# ds: sequence

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04 Apr 2005, 16:39
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plz explain
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Manager
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04 Apr 2005, 19:19
Ans is 'D'

Stmt 1 -
Let F4 = 5, F2 = 2, F6 = 3
N= 523523 --> is divisible by 7

If N = 438438 --> this is alos divisible by 7
This shld be true for all other cominations also.
Stmt 1 is sufficient

Stmt 2:
N = 1111111
This is divisible by 7.
-> Any multiple of N will be divisible by 7
Stmt 2 is sufficient

Ans = 'D'
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04 Apr 2005, 19:33
ssap wrote:
Ans is 'D'

Stmt 1 -
Let F4 = 5, F2 = 2, F6 = 3
N= 523523 --> is divisible by 7

If N = 438438 --> this is alos divisible by 7
This shld be true for all other cominations also.
Stmt 1 is sufficient

Stmt 2:
N = 1111111
This is divisible by 7.
-> Any multiple of N will be divisible by 7
Stmt 2 is sufficient

Ans = 'D'

How did you take values for the statement1? Please explain
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04 Apr 2005, 19:55
oh, it is D, mis-calculations.

Last edited by MA on 05 Apr 2005, 16:28, edited 1 time in total.
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05 Apr 2005, 06:22
Assume value for F(1), F(2), F(3) etc.
Since no restrictions are given, except that N is a 6 digit integer number, assume integer values for each of those.
+ve or -ve does not matter as this problem tests only divisibility rules.
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05 Apr 2005, 06:39
(1) F(1)=F(4), F(2)=F(5), F(3)= F(6)
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))
1001/7=143 divisible by 7
Therefore N is divisible by 7

(2) is a special case of (1) So N is also divisible by 7.

(D)
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05 Apr 2005, 10:17
it should be E

because how do we know that in statement 1 all numbers are distinct??
i mean if F4=5 then F2=5 as well, we dont know right???

so the number could 555555? is that divisible by 7?
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05 Apr 2005, 14:35
HongHu wrote:
(1) F(1)=F(4), F(2)=F(5), F(3)= F(6)
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))
1001/7=143 divisible by 7
Therefore N is divisible by 7

(2) is a special case of (1) So N is also divisible by 7.

(D)

I thought NF(k) was the number format....Now I got it
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06 Apr 2005, 12:50
How did you get this? Pls explain:
HongHu wrote:
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))
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06 Apr 2005, 16:26
mirhaque wrote:
How did you get this? Pls explain:
HongHu wrote:
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))

option 1 says F4=F1

Since F4 is mutiplied by 1000 and F1=F4(given)

1000F4 + F1 = 1001F4 (Since F1=F4)
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06 Apr 2005, 17:19
i realized these are digits in a number.....they cant be the same!

D it is...
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07 Apr 2005, 09:31
They CAN be the same. 555555 is divisible by 7.
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07 Apr 2005, 09:31
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