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# ds: set

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Senior Manager
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ds: set [#permalink]  04 Apr 2005, 15:56
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pls explain
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Manager
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[#permalink]  04 Apr 2005, 19:02
Ans 'C'

Stmt 1: Least element in either set is 6
This cld be S= {6,9,12}& T= {6,12}
Median of S = 9, Median of T=9 -> Botrh are the same
If S ={6,9} & T= {6,12}, Median os S = 7.5, median of T = 9
=> 1 is not suff

Stmt 2: Set T contains twice the no of elements of Set S
=> Insuff as result cld vary depending on the actual members of each set.

Stmt 1 & 2 together:
S={6,12} - median = 9
T={6,12,18,24} - median = 30
Median of S < MEdian of T
=> 'C'
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[#permalink]  05 Apr 2005, 03:57
C) !

1) no information about the number of element in the set => insuff

2) could be +ve or -ve => in suff

1) + 2) S=>6,9 T=>6,12,18,24 T>S
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[#permalink]  05 Apr 2005, 06:24
christoph wrote:
C) !

1) no information about the number of element in the set => insuff

2) could be +ve or -ve => in suff

1) + 2) S=>6,9 T=>6,12,18,24 T>S

Cristoph,
I like the statement in your signature - very inspiring!
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[#permalink]  05 Apr 2005, 06:42
For (2) you don't know the starting number or ending number of both sets so you don't know where they are in the number axis, and it's not sufficient to compare the size of their medians.
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[#permalink] 05 Apr 2005, 06:42
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# ds: set

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