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DS - SET 22 Q16 - SERIES

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Senior Manager
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DS - SET 22 Q16 - SERIES [#permalink] New post 09 Oct 2007, 14:14
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Series problem
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Re: DS - SET 22 Q16 - SERIES [#permalink] New post 09 Oct 2007, 14:44
singh_amit19 wrote:
Series problem


I. If t3 is 1/4, then t5 = 1/4*1/2*1/2 = 1/16. SUFF.

II. If t1 - t5 = 15/16, then t1 - (t1/2^4) = 15/16.

t1 - (t1/16) = 15/16

16t1 - t1 = 15.

t1 = 1

t5 = 15/16. SUFF.

It's D. (Although, in each case, you don't have to actually solve for t5. Knowing any value in the series will allow you to determine any other value. I obviously gives you a value in the series. II allows you to set up an equation that will give you such a value.)
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 [#permalink] New post 09 Oct 2007, 15:32
i get D...

(1) simple.. its sufficient

(2) t5=t4/2=t3/4=t2/8=t1/16

t1-t1/16=15/16

solve..you know the value of t1...now you know the value of t5...sufficient
  [#permalink] 09 Oct 2007, 15:32
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DS - SET 22 Q16 - SERIES

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