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DS: Tough Geometry (GMATPrep)

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DS: Tough Geometry (GMATPrep) [#permalink] New post 18 Jun 2006, 13:06
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 [#permalink] New post 18 Jun 2006, 13:41
write the equation and express height of larger trangle in terms of height of smaller triangle

S/s = H/h (equal ratios since angles are equal)
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 [#permalink] New post 18 Jun 2006, 17:23
gmatmba wrote:
write the equation and express height of larger trangle in terms of height of smaller triangle

S/s = H/h (equal ratios since angles are equal)


Great! Thanks. Dunno how I missed it.

It's like you know the rule but you forget to apply it. Then someone reminds you and you feel like this... :oops: :roll: :cry: :twisted:
  [#permalink] 18 Jun 2006, 17:23
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