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# DS: Triangle

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Manager
Joined: 15 Sep 2006
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26 Nov 2007, 20:29
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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CEO
Joined: 17 Nov 2007
Posts: 3580
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
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26 Nov 2007, 22:24
Expert's post
C.

1. angle ABC=30. we can move AC with constant angle ABC and obtain different area - INSUFF.

2. L=18Pi ==> d=18 ==> AB is diameter
but different angles ABC give us different area. - INSUFF

1&2. Area=1/2*(root(3)/2*18)*(1/2*18) - SUFF
CEO
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26 Nov 2007, 23:41

C.

S1: Key here is to realize that triangle ABC isnt said to be inscribed, so we cant assume its a right triangle.

S2: says its a right triangle b/c C=18pi. (if any two points equal the diameter of a circle of a triangle, then that triangle is inscribed).

But we dont know the other sides

Together we can assess its a 30, 60, 90 triangle.
SVP
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17 Dec 2007, 07:34
was leaning towards C as well, but kinda fluked out as I had forgotten some of the properties, especially the one about the stem not saying triangle was inscribed....i just assumed it
Director
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17 Dec 2007, 07:53
How do you know that AB is the diameter? It's not specifically stated anywhere, so you cannot conclude that the triangle is a right (30/60/90) triangle.
CEO
Joined: 17 Nov 2007
Posts: 3580
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
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Kudos [?]: 2801 [0], given: 359

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17 Dec 2007, 08:31
Expert's post
sonibubu wrote:
How do you know that AB is the diameter? It's not specifically stated anywhere, so you cannot conclude that the triangle is a right (30/60/90) triangle.

from second statement we have a diameter of circle: 18Pi=Pi*D ==> D=18.

AB is also 18 from question. There is only one possibilitiy: AB=D otherwise AB would be less than D=18
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