Find all School-related info fast with the new School-Specific MBA Forum

It is currently 20 Oct 2014, 21:39

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

DS: X^2+ BX+ C=0,---> R,S are solutions of the

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Manager
Manager
avatar
Joined: 08 Apr 2004
Posts: 137
Location: Corea
Followers: 1

Kudos [?]: 95 [0], given: 0

DS: X^2+ BX+ C=0,---> R,S are solutions of the [#permalink] New post 07 Sep 2004, 06:24
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
DS: X^2+ BX+ C=0,---> R,S are solutions of the equation.Is R* S>0?
1. B<0
2. C<0
Director
Director
avatar
Joined: 20 Jul 2004
Posts: 593
Followers: 1

Kudos [?]: 29 [0], given: 0

 [#permalink] New post 07 Sep 2004, 06:49
B.

Since R and S are solutions of the equation, the equation can be written as x^2 - (R+S)x + RS = 0

In this case, B = -(R+S) and C = RS.
From II, C < 0 => RS < 0, Ans to the question: No.
Joined: 31 Dec 1969
Location: United States
Concentration: Marketing, Other
GPA: 3.64
WE: Accounting (Accounting)
Followers: 0

Kudos [?]: 69 [0], given: 78520

CAT Tests
 [#permalink] New post 07 Sep 2004, 07:59
For the roots to be real and distinct in a quadratic equation, the determinant b^2-4ac > o

here b = B
c=C
a = 1

so, w have B^2 - 4C > 0

Now, 1) B < 0. Doesn't matter as B^2 is always +ve. So we dont know if B^2- 4C will be +ve or not. So insufficient

2) C<0. Sufficient. The B^2 - 4C will be > than 0.

Hence B.
Director
Director
User avatar
Joined: 16 Jun 2004
Posts: 893
Followers: 1

Kudos [?]: 10 [0], given: 0

 [#permalink] New post 07 Sep 2004, 08:00
guest was me..sorry forgot to login earlier.
Manager
Manager
avatar
Joined: 02 Apr 2004
Posts: 224
Location: Utrecht
Followers: 1

Kudos [?]: 7 [0], given: 0

 [#permalink] New post 07 Sep 2004, 11:13
Great work guys!

I took C as answer, while now it is obvious for me as well that B is sufficient. We need to understand the value of C to answer the question.

Regards,

Alex
  [#permalink] 07 Sep 2004, 11:13
    Similar topics Author Replies Last post
Similar
Topics:
3 Experts publish their posts in the topic In the equation x^2+bx+c=0, b and c are constants, and x is idinuv 1 06 Mar 2014, 20:26
25 Experts publish their posts in the topic If r and s are the roots of the equation x^2 + bx + c = 0 asveaass 19 20 Oct 2012, 11:12
How many integers can let x^2+bx+c=0? B and c are constants. apollo168 2 18 Aug 2006, 22:33
x^2+bx+c=0 b,c are constant integers, how many pairs of getzgetzu 5 06 May 2006, 02:44
How many integers can let x^2+bx+c=0? B and c are constants. DLMD 18 16 Feb 2005, 23:03
Display posts from previous: Sort by

DS: X^2+ BX+ C=0,---> R,S are solutions of the

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.