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# ds.x^3*y ^4=5000, y =? 1) y is a positive integer 2) x is a

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Manager
Joined: 08 Apr 2004
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ds.x^3*y ^4=5000, y =? 1) y is a positive integer 2) x is a [#permalink]

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09 Sep 2004, 21:41
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

ds.x^3*y ^4=5000, y =?
1) y is a positive integer
2) x is a integer.
Director
Joined: 05 May 2004
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Location: San Jose, CA
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09 Sep 2004, 22:17
marine wrote:
ds.x^3*y ^4=5000, y =?
1) y is a positive integer
2) x is a integer.

C

1 not sufficient .... x can be integer/not integer ... anything!
2 not sufficient .... y can be integer/not integer ... anything!

Together
x=2 ... y^4=625 or y=5
x=5 ... y^4=40 ... y is not integer
same for other values of X

Hence, y=5
Director
Joined: 31 Aug 2004
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10 Sep 2004, 08:04
I choose A.

To me the sole not integer way is when both x and y are relative numbers, example : (2/5)^3.(5/2.sgrt(sqrt(2000))

if either x or y is integer then both are, unique issue is y sign and statement 2 does not answer it.
Senior Manager
Joined: 22 Jun 2004
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10 Sep 2004, 08:15
I think it is C. 5000 = 2^3 * 5^4

(1) y is an integer. Say it is 2^4. 5000/16 and x has a vlaue.
It can also be 3^4 because x has a different value. It is because nothing is said about x-whether real or integer.

(2)Same logic applies here too.

Take 1 and 2 and it is very easy to arrive at y which is 5. Good twist is x is an integer and y is a positive integer. These constraints are necessary because the power of y is even and hence y can be +ve or -ve. Because x's power is odd, sign is reflected in the calculation.

marine wrote:
ds.x^3*y ^4=5000, y =?
1) y is a positive integer
2) x is a integer.

_________________

Awaiting response,

Thnx & Rgds,
Chandra

Manager
Joined: 02 Apr 2004
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10 Sep 2004, 08:23
I will choose C too.

st.1
y could be 1 or 2 or 3, because x could be anything.
not sufficient.

st.2
x could be 1, or 2 or 3 and we could not know the value of y. it could be an integer or not integer.

Both statements together are sufficient to solve the value of y, because x must be an integer and y must be an positive integer. x canÂ´t be an negative integer.

Please correct me if I am wrong.

Regards,

Alex
Director
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10 Sep 2004, 09:04
5000 = 2^3.5^4

so if we assume that either x or y is an integer there is only one way to allocate values...
Senior Manager
Joined: 22 Jun 2004
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10 Sep 2004, 09:11
Why should the other be integer? It can be a real number with recurring decimals!! We just cannot say because any damn number has got cubed root.

twixt wrote:
5000 = 2^3.5^4

so if we assume that either x or y is an integer there is only one way to allocate values...

_________________

Awaiting response,

Thnx & Rgds,
Chandra

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