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DS: x^4+^4>z^4

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Senior Manager
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Joined: 31 Jul 2006
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DS: x^4+^4>z^4 [#permalink] New post 07 Oct 2006, 18:19
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Please explain the answer. Thx!
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Manager
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Re: DS: x^4+^4>z^4 [#permalink] New post 07 Oct 2006, 19:05
2 is not sufficient.

(-2) + (-3) > -10
but (-2)^4 + (-3)^4 < (-10)^4

On the other hand (10)+ (9) > 1
(10)^4 + 9^4 > 1^4

1 is also not sufficient
Ex 1: 1+1>1
1^2 + 1^2 > 1^2
Ex2 : 4^2 + 5^2 > 6^2
but 16^2+25^2 < 36^2

Hence the answer is (E)?
Senior Manager
Senior Manager
User avatar
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 4 [0], given: 0

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Re: DS: x^4+^4>z^4 [#permalink] New post 07 Oct 2006, 19:22
mst wrote:
2 is not sufficient.

(-2) + (-3) > -10
but (-2)^4 + (-3)^4 < (-10)^4

On the other hand (10)+ (9) > 1
(10)^4 + 9^4 > 1^4

1 is also not sufficient
Ex 1: 1+1>1
1^2 + 1^2 > 1^2
Ex2 : 4^2 + 5^2 > 6^2
but 16^2+25^2 < 36^2

Hence the answer is (E)?


Yes OA is E. Great explanation, I thought x^2+y^2 would satisfy all conditions, it's interesting as the powers increase the condition may change.
Re: DS: x^4+^4>z^4   [#permalink] 07 Oct 2006, 19:22
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DS: x^4+^4>z^4

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