DS - x and y positive integers : DS Archive
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# DS - x and y positive integers

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DS - x and y positive integers [#permalink]

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11 Apr 2007, 02:03
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This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the answer to this question? When the main stem of the question says, positive integers the exlanation for statement 1 used negative numbers to prove its case that statement 1 was not sufficient.

This confused me a little... Anyone who can clear my misconception?
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SVP
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11 Apr 2007, 03:40
It's (A)

With y = 2*x, we have

4^x * (1/3)^y
= 2^(2*x) * (1/3)^(2*x)
= (2/3)^(2*x) < 1 as x > 0

It's stated that x & y are both positive integers... Your answer was correct
Senior Manager
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11 Apr 2007, 04:15
Phew!! Thanks Fig!! Appreciate it!!
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11 Apr 2007, 04:17
axl_oz wrote:
Phew!! Thanks Fig!! Appreciate it!!

U are welcome :D
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11 Apr 2007, 06:39
4^x(1/3)^y can be written as (4^x/3^y)

St1:
y = 2x, so we have (4^x/3^y) = (4^x/3^2x) = (4^x/9^x) = (4/9)^x. This is always less than 1. Sufficient.

St2:
y = 4, so we have (4^x/81). We don't know x, so we can't tell if it's smaller or greater than 1. Insufficient.

Ans A
11 Apr 2007, 06:39
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